Two types of decimals are :
Terminating decimal |
Non Terminating and Recurring Decimal | |
A decimal which ends with countable number of digits is known as terminating decimal. For example, 0.25, 0.5, ............... etc |
Non terminating decimal means, it will not end up with any number. For example, 0.525252.............. 0.125125.............. |
To convert a terminating decimal to fraction, we have to follow the steps given below.
Step 1 :
First count the number of digits after the decimal point.
Step 2 :
By multiplying by 10, 100, 1000, ......... etc, we may get rid of the decimal point.
Fro example, if we have only two digits after the decimal point, we have to multiply both numerator and denominator by 100.
Step 3 :
If it is possible, we may simplify the numerator and denominator separately.
To know, how to convert a non-terminating recurring decimal to fraction,
Convert the following decimals to fractions in the form p/q, where p and q are integers and q ≠ 0.
Example 1 :
0.35
Solution :
Number of digits after the decimal point is 2.
So, we have to multiply both numerator and denominator by 100.
0.35 x (100/100) = 35/100
We may simplify both numerator and denominator by 5 times table.
= 7/20
Example 2 :
2.176
Solution :
Number of digits after the decimal point is 3.
So, we have to multiply both numerator and denominator by 1000.
2.176 x (1000/1000) = 2176/1000
We may simplify both numerator and denominator
= 1088/500
= 544/250
= 272/125
Example 3 :
0.33333.............
Solution :
Let x = 0.3333........... (1)
Number of digits in the repeating pattern is 1. That is 3.
Because there is only one digit in the repeating pattern, multiply both sides of (1) by 10.
10x = 3.333......... (2)
(2) - (1) ==>
10x - x = 3.333.........00
9x = 3
Divide each side by 9.
x = 3/9
x = 1/3
Example 4 :
0.6868.........
Solution :
Let x = 0.6868........... (1)
Number of digits in the repeating pattern is 2. That is 68.
Because there are two digits in the repeating pattern, multiply both sides of (1) by 100.
100x = 68.6868............... (2)
(2) - (1)==>
100x - x = 68.6868.........0
99x = 68
Divide each side by 99.
x = 68/99
Example 5 :
32.03256256256..........
Solution :
Let x = 32.03256256256.............
Here, the repeated pattern is 256
No. of digits between the 1st repeated pattern and decimal is 2.
So, multiply the given decimal by 100. Then, we have
100x = 3203.256256256...............(1)
No. of digits between the 2nd repeated pattern and decimal = 5
So, multiply the given decimal by 100000. Then, we have
100000x = 3203256.256256256...............(2)
Subtracting (1) from (2), we get
(2) - (1) ===>
99900x = 3200053
x = 3200053/99900
Calculate the following and write the answer as fraction.
Example 6 :
0.25 + 1/4
Solution :
0.25 + 1/4
Now, we can convert the decimal into fraction. For that we observe the number of digits after the decimal. It is 2 digits.
= 25/100 + 1/4
To add these two fractions, we have to make the denominators same.
= 25/100 + (1/4) ⋅ 25/25
= 25/100 + 25/100
= (25 + 25)/100
= 50/100
After the simplification, we get
= 1/2
Example 7 :
By how much is 3/5 of 75 greater than 4/7 of 77 ?
Solution :
First let us find each quantities clearly and then we can find the difference.
= 3/5 of 75
= (3/5) ⋅ 75
= 3 ⋅ 15
= 45
4/7 of 77 = (4/7) ⋅ 77
= 4 ⋅ 11
= 44
To find how much more it is, we have to find the difference
= 45 - 44
= 1
So, 4/7 of 77 is 1 more than 3/5 of 75.
Example 8 :
Andrew is practicing basketball. She makes a basket from the free throw line 8 out of 25 shots. Which decimal shows the fraction Andrew's shots that results in the basket ?
a) 3.2 b) 3.125 c) 0.32 d) 0.3125
Solution :
total number of shots = 25
Number of shorts that she makes into the basket = 8
= 8/25
= (8/25) ⋅ (4/4)
= 32/100
= 0.32
So, option c is correct.
Example 9 :
Evaluate (2.39)2 - (1.61)2 / (2.39 - 1.61)
Solution :
= (2.39)2 - (1.61)2 / (2.39 - 1.61)
Comparing the numerator using algebraic identity, we get
a2 - b2 = (a + b)(a - b)
= (2.39 + 1.61) (2.39 - 1.61) / (2.39 - 1.61)
= 2.39 + 1.61
= 4
Example 10 :
Joe's apple weights 4/5 lb. Marta's weighs 0.5 lb. How much more does Joe's apple weigh than Marta's ?
a) 0.3 lb b) 0.8 lb c) 0.75 lb d) 1.25 lb
Solution :
Weight of Joe's apple = 4/5
Converting into decimal, we can do the comparison simply.
= (4/5) ⋅ (20/20)
= 80/100
= 0.80 lb
Weight of Marta's apple = 0.5 lb
Difference = 0.8 - 0.5
= 0.3 lb
So, Joe's apple is 0.3 lb more than Marta's apple.
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