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To evaluate a linear expression, replace the variable or variables by the given values and simplify using order of operations or PEMDAS.
PEMDAS is the rule that can be used to simplify or evaluate complicated numerical expressions with more than one binary operation.
P ----> Parentheses
E ----> Exponent
M ----> Multiply
D ----> Divide
A ----> Add
S ----> Subtract
Important Notes :
1. In a particular simplification, if you have both multiplication and division, do the operations one by one in the order from left to right.
2. Division does not always come before multiplication. We have to do one by one in the order from left to right.
Evaluate the following linear expressions using the given values of the variables.
Example 1 :
y ÷ 2 + x; x = 1 and y = 2
Solution :
= y ÷ 2 + x
Substitute x = 1 and y = 2.
= 2 ÷ 2 + 1
= 1 + 1
= 2
Example 2 :
x + 2y; x = 9 and y = 10
Solution :
= x + 2y
Substitute x = 9 and y = 10.
= 9 + 2(10)
= 9 + 20
= 29
Example 3 :
z(x + y); x = 6, y = 8 and z = 6
Solution :
= z(x + y)
Substitute x = 6, y = 8 and z = 6.
= 6(6 + 8)
= 6(14)
= 84
Example 4 :
(y + x) ÷ 2 + x; x = 1 and y = 1
Solution :
= (y + x) ÷ 2 + x
Substitute x = 1 and y = 1.
= (1 + 1) ÷ 2 + 1
= 2 ÷ 2 + 1
= 1 + 1
= 2
Example 5 :
z - (y ÷ 3 - 1); y = 3, and z = 7
Solution :
= z - (y ÷ 3 - 1)
Substitute y = 3 and z = 7.
= 7 - (3 ÷ 3 - 1)
= 7 - (1 - 1)
= 7 - 0
= 7
Example 6 :
p - (9 - (m + q)); m = 4, p = 5 and q = 3
Solution :
= p - (9 - (m + q))
Substitute m = 4, p = 5 and q = 3.
= 5 - (9 - (4 + 3))
= 5 - (9 - 7)
= 5 - 2
= 3
Example 7 :
y - (4 - x - y ÷ 2); x = 3, and y = 2
Solution :
= y - (4 - x - y ÷ 2)
Substitute x = 3 and y = 2.
= 2 - (4 - 3 - 2 ÷ 2)
= 2 - (4 - 3 - 1)
= 2 - (4 - 4)
= 2 - 0
= 2
Example 8 :
y ÷ 5 + 1 + x ÷ 6; x = 6, and y = 5
Solution :
= y ÷ 5 + 1 + x ÷ 6
Substitute x = 6 and y = 5.
= 5 ÷ 5 + 1 + 6 ÷ 6
= 1 + 1 + 1
= 3
Example 9 :
x - (5 - 2(y + z)); x = 4, y = 5, and z = 3
Solution :
= x - (5 - 2(y + z))
Substitute x = 4, y = 5 and z = 3.
= 4 - (5 - 2(5 + 3))
= 4 - (5 - 2(8))
= 4 - (5 - 16)
= 4 - (-11)
= 4 + 11
= 15
Example 10 :
6q + (2m + 1) ÷ 17; m = 8, and q = 3
Solution :
= 6q + (2m + 1) ÷ 17
Substitute m = 8 and q = 3.
= 6(3) + (2(8) + 1) ÷ 17
= 18 + (16 + 1) ÷ 17
= 18 + 17 ÷ 17
= 18 + 1
= 19
Example 11 :
Debbie bought 4 boxes of black pens and 6 boxes of red pens. Each box has 8 pens in it. Which expression could Debbie use to find the total number of pens she bought?
a) (8 × 6) + 4 b) (8 × 4) + 6 c) 8 + (4 × 6)
d) 8 × (4 + 6)
Solution :
Number of boxes of black pens = 4
Number of boxes of red pens = 6
Number of pens in each box = 8
Total number of pens = 4 x 8 + 6 x 8
= 8 x (4 + 6)
So, option d is correct.
Example 12 :
What is the value of the expression below?
3 x 105 + 4 x 103 + 8 x 102 + 1 x 101
a) 3,481 b) 34,810 c) 304,810 d) 3,000,481
Solution :
= 3 x 105 + 4 x 103 + 8 x 102 + 1 x 101
= 3 x 100000 + 4 x 1000 + 8 x 100 + 1 x 10
= 300000 + 4000 + 800 + 10
= 304810
So, option c is correct.
Example 13 :
After m months, the length of a finger nail is 10 + 3m millimeters. How long is the finger nail after eight months? three years?
Solution :
Length of finger nail = 10 + 3m
Here m represents number of months.
Length of nail after 8 months :
= 10 + 3(8)
= 10 + 24
= 34 mm
Length of nail after three years :
1 year = 12 months
3 years = 3(12)
= 36 months
= 10 + 3(36)
= 10 + 108
= 118 mm
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