EQUATION OF A CIRCLE IN STANDARD FORM WORKSHEET

Question 1 :

Write the equation of a circle in standard form whose center is (3, 2) and radius is 6.

Question 2 :

Write the equation of a circle in standard form whose center is (0, -3) and radius is 7.

Question 3 :

If two end points of the diameter of a circle are (-1, -2) and (11, 14), find the equation of the circle in standard form. 

Question 4 :

Write the following general form of equation of the circle in standard form. And find the center and radius. 

x2 + y- 4x + 6y - 12  =  0

Question 5 :

The point (1 ,2) is on a circle whose center is (5, -1).  Write the equation of the circle in standard equation. 

Question 6 :

Find the equation of the circle shown below in standard form.

1. Answer :

Equation of a circle in standard form :

(x - h)2 + (y - k)2  =  r2

Substitute (h, k) = (3, 2) and r = 6.

(x - 3)2 + (y - 2)2  =  62

(x - 3)2 + (y - 2)2  =  36

2. Answer :

Equation of a circle in standard form :

(x - h)2 + (y - k)2  =  r2

Substitute (h, k) = (0, -3) and r = 7.

(x - 0)2 + [y - (-3)2]  =  72

x2 + (y + 3)2  =  72

3. Answer :

Using mid point formula, find the mid point of the diameter.  

Mid point of (-1, -2) and (11, 14) : 

=  [(-1 + 11)/2, (-2 + 14)/2]

=  (10/2, 12/2)

=  (5, 6)

Mid point of the diameter is the center of the circle. 

So, the center of the circle is (5, 6). 

Using distance formula to find the distance between the center and one of the end points of the diameter.

Distance between (5, 6) and (11, 14) :

=  √[(11 - 5)2 + (14 - 6)2]

=  √[62 + 82]

=  √[36 + 64]

=  √100

=  10

Radius of the circle is 10 units. 

Equation of the circle in standard form : 

(x - h)2 + (y - k)2  =  r2

Substitute (h, k) = (5, 6) and r = 10.

(x - 5)2 + (y - 6)2  =  102

4. Answer :

x2 + y- 4x + 6y - 12  =  0

Write x-terms and y-terms together. 

x2 - 4x + y2 + 6y - 12  =  0

Completing the square. 

x2 - 2(x)(2) + 22 - 2+ y2 + 2(y)(3) + 3232 - 12  =  0

(x - 2)2 - 2+ (y + 3)32 - 12  =  0

(x - 2)2 - 4 + (y + 3)- 9 - 12  =  0

(x - 2)+ (y + 3)25  =  0

Add 25 to each side.

(x - 2)+ (y + 3)2  =  25

(x - 2)+ (y + 3)2  =  52

The above equation of the circle is in standard form.  

Center (h, k)  =  (2, -3)

Radius  =  5

5. Answer :

To find the standard equation of the circle, we need to know the center and radius. The center is already given and we need to find the radius.

Using distance formula, we have

Radius  =  √[(5 - 1)2 + (-1 - 2)2]

Radius  =  √[42 + (-3)2]

Radius  =  √[16 + 9]

Radius  =  √25

Radius  =  5

Equation of a circle in standard form : 

(x - h)2 + (y - k)2  =  r2

Substitute (h, k) = (5, -1) and r = 5.

(x - 5)2 + [y - (-1)2]  =  52

Simplify. 

(x - 5)2 + (y + 1)2  =  52

6. Answer :

In the given circle, measure the length of the radius.

The circle above has the center (5, 2) and radius 4 units.

Equation of the circle in standard form :

(x - h)2 + (y - k)2 = r2

Substitute (h, k) = (5, 2) and r = 4.

(x - 5)2 + (y - 2)2 = 42

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