Derivative of e to the Power Sin Square Root x

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We know the derivative of ex, which is ex.

(ex)' = ex

We can find the derivative of esin√x using chain rule.

Find α΅ˆΚΈβ„dβ‚“, if

y = esin√x

Let u = √x.

y = esinu

Let v = sinu.

y = ev

Now,

y = ev ----> y is a function of v

v = sinu ----> v is is a function of u

u = √x ----> u is is a function of x

By chain rule, the derivative of y with respect to x :

Substitute y = ev, v = sinu and u = βˆšx.

Substitute v = sinu.

Substitute u = √x.

Therefore,

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