We know the derivative of ex, which is ex.
(ex)' = ex
We can find the derivative of esecx using chain rule.
If y = esecx, find ᵈʸ⁄dₓ.
y = esecx
Let u = secx.
Then, we have
y = eu
Now, y = eu and u = secx. That is, y is a function of u and u is a function of x.
By chain rule, the derivative of y with respect to x :
Substitute y = eu and u = secx.
Substitute u = secx.
Therefore,
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