SOLVING LINEAR EQUATIONS USING CROSS MULTIPLICATION METHOD

This is one of the methods we use to solve system of linear equations.

Let us consider the following system of linear equations. 

a1x + b1y + c1  =  0

a2x + b2y + c2  =  0

We have to write the coefficients of the equations and do cross multiplication as shown below. 

We write the coefficient of y and constant term and two more columns by repeating the coefficients of x and y as follows. 

The result is given by

The solution is

Solve the following system of equations using cross multiplication method.

(i)   3x + 4y = 24, 20x - 11y = 47

(ii)  0.5x + 0.8y = 0.44 , 0.8x + 0.6y = 0.5

(iii) (3x/2) - (5y/3) = -2 , (x/3) + (y/2) = 13/6

(iv) (5/x)-(4/y)  =  -2 , (2/x)+(3/y)  =  13

Detailed Solution

(i)   3x + 4y  =  24, 20x - 11y  =  47

Solution :

3x + 4y - 24 = 0    ----- (1)

20x - 11y - 47 = 0 ----- (2)

x/(-188-264)  = y/(-480 -(-141))   = 1/(-33-80)

x/(-452)  = y/(-480+141))   = 1/(-33-80)

x/(-452)  = y/(-339)   = 1/(-113)

x/(-452)  =  1/(-113)

x  =  (-452)/(-113)

x  =  4

y/(-339)  =  1/(-113) 

y  =  (-339)/(-113)

y  =  3

So, the solution is (4, 3).

(ii)  0.5x + 0.8y = 0.44 , 0.8x + 0.6y = 0.5

Solution :

0.5x+0.8y  =  0.44  ----- (1)

0.8x+0.6y  =  0.5  ----- (2)

To make the decimal numbers into integers, we have to multiply the first equation by 100 and the second equation by 10.

50x+80y-44  =  0 ----- (1)

8x+6y-5  =  0  ----- (2)

x/(-400-(-264))  =  y/(-352 -(-250))  =  1/(300-640)

x/(-400+264)   =  y/(-352+250))  =  1/(-340)

x/(-136)  =  y/(-102)  =  1/(-340)

x/(-136)  =  1/(-340)

x  =  (-136)/(-340)

x  =  0.4

y/(-102)  =  1/(-340) 

y  =  (-102)/(-340)

y  =  0.3

So, the solution is (0.4, 0.3).

(iii) (3x/2) - (5y/3) = -2 , (x/3) + (y/2) = 13/6

Solution :

9x - 10y  =  -12

(2x + 3y)/6  =  13/6

9x-10y+12  =  0 ----- (1)

2x+3y-13  =  0 ----- (2)

x/(130-36)  =  y/(24 -(-117))  =  1/(27-(-20))

x/(94)  =  y/(24+117))  =  1/(27+20)

x/(94)  =  y/(141)  =  1/(47)

x/(94)  =  1/(47)

x  =  94/47

x  =  2

y/(141)  =  1/(47) 

y  =  (141)/(47)

y  =  3

So, the solution is (2, 3).

(iv) (5/x)-(4/y)  =  -2 , (2/x)+(3/y)  =  13

Solution :

Let 1/x = a and 1/y = b

5a-4b  =  - 2   

2a+3 b  =  13   

5a - 4b + 2 = 0   ----- (1)

2a + 3b - 13 = 0  ----- (2)

a/(52-6)  =  b/(4 -(-65))   =  1/(15-(-8))

a/46  =  b/(4 +65)   =  1/(15+8)

a/(46)   =  b/(69)   =  1/(23)

a/(46)   =  1/(23)

a  =  46/23

 a  =  2

b/(69)   =  1/(23) 

b  =  69/23

b = 3

x  =  1/2 and y  =  1/3

So, the solution is (1/2, 1/3).

Apart from the stuff given in this section, if you need any other stuff in math, please use our google custom search here.

Kindly mail your feedback to v4formath@gmail.com

We always appreciate your feedback.

©All rights reserved. onlinemath4all.com

Recent Articles

  1. Printable Math Worksheets

    Apr 20, 24 12:02 AM

    Printable Math Worksheets - Worksheets in Pdf formats from grade 1 to 10

    Read More

  2. Printable Math Worksheets for Grade 2

    Apr 19, 24 11:58 PM

    Printable Math Worksheets for Grade 2

    Read More

  3. Sequences and Series

    Apr 19, 24 11:45 PM

    Sequences and Series - Concept - Examples

    Read More