**Angle pair relationships :**

In this section, we are going to study about different relationships between pairs of angles.

Two angles are vertical angles, if their sides form two pairs of opposite rays.

m∠1 and m∠3 are vertical angles

m∠2 and m∠4 are vertical angles

Two adjacent angles are a linear pair, if their non-common sides are opposite rays.

m∠5 and m∠6 are a linear pair.

**Example 1 :**

Look at the picture shown below and answer the following questions.

(i) Are m∠2 and m∠3 a linear pair ?

(ii) Are m∠3 and m∠4 a linear pair ?

(iii) Are m∠1 and m∠3 vertical angles ?

(iv) Are m∠2 and m∠4 vertical angles ?

**Solution : **

**Solution (i) : **

No. The angles are adjacent but their non-common sides are not opposite rays.

**Solution (ii) : **

Yes. The angles are adjacent and their non-common sides are opposite rays.

**Solution (iii) : **

No. The sides of the angles do not form two pairs of opposite rays.

**Solution (iv) : **

No. The sides of the angles do not form two pairs of opposite rays.

**Example 2 :**

In the stair railing shown at the right, m∠6 has a measure of 130°. Find the measures of the other three angles.

**Solution : **

m∠6 and m∠7 are a linear pair. So, the sum of their measures is 180°.

m∠6 + m∠7 = 180°

Substitute m∠6 = 130°

130° + m∠7 = 180°

Subtract 130° from both sides.

m∠7 = 50°

m∠6 and m∠5 are also a linear pair. So, it follows that m∠7 = 50°.

m∠6 and m∠8 are vertical angles. So, they are congruent and they have same measure.

m∠8 = m∠6 = 130°

**Example 3 :**

In the diagram shown below, Solve for "x" and "y". Then, find the angle measures.

**Solution : **

Use the fact that the sum of the measures of angles that form a linear pair is 180°.

**Solving for "x" :**

m∠AED and m∠DEB are a linear pair. So, the sum of their measures is 180°.

m∠AED + m∠DEB = 180°

Substitute m∠AED = (3x+5)° and m∠DEB = (x+15)°.

(3x+5)° + (x+15)° = 180°

Simplify.

4x + 20 = 180

Subtract 20 from both sides.

4x = 160

Divide both sides by 4.

x = 40

**Solving for "y" :**

m∠AEC and m∠CEB are a linear pair. So, the sum of their measures is 180°.

m∠AEC + m∠CEB = 180°

Substitute m∠AEC = (y+20)° and m∠CEB = (4y-15)°.

(y+20)° + (4y-15)° = 180°

Simplify.

5y + 5 = 180

Subtract 5 from both sides.

5y = 175

Divide both sides by 5.

y = 35

**Use substitution to find the angle measures :**

m∠AED = (3x + 5)° = (3 • 40 + 5)° = 125°

m∠DEB = (x + 15)° = (40 + 15)° = 55°

m∠AEC = ( y + 20)° = (35 + 20)° = 55°

m∠CEB = (4y º 15)° = (4 • 35 º 15)° = 125°

So, the angle measures are 125°, 55°, 55°, and 125°. Because the vertical angles are congruent, the result is reasonable.

After having gone through the stuff given above, we hope that the students would have understood "Angle pair relationships".

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