ALGEBRA WORD PROBLEMS
In this section, you will learn how to solve algebra word problems step by step.
Solving Algebra Word Problems - Steps
Step 1 :
Read the question twice and understand the information clearly. Because, always it is very important to understand the information given in the question.
Step 2 :
If it is possible, we have to split the given information. Because, when we split the given information in to parts, we can understand them easily.
Step 3 :
Once we understand the given information clearly, solving the word problem in algebra will not be a challenging one.
Step 4 :
When we try to solve the word problems, we have to introduce "x" or y" or some other alphabet for unknown value ( = answer for our question). Finally we have to get value of the alphabet which was introduced for the unknown value.
Step 5 :
If it is required, we have to draw picture for the given information. Drawing picture for the given information will give us a clear understanding about the question.
Step 6 :
Using the alphabet introduced for unknown value, we have to translate the English statement (information) given in the question as mathematical equation.
In translation, we have to translate the following English words as the corresponding mathematical symbols.
of -----> x (multiplication)
am, is, are, was, were, will be, would be -----> = (equal)
Step 7 :
Once we have translated the English Statement (information) given in the question as mathematical equation correctly, 90% of the work will be over. The remaining 10% is just getting the answer. That is solving for the unknown.
These are the steps most commonly involved in solving word problems in Algebra.
Let us see how the above explained steps work in solving word problem in algebra.
Question :
The denominator of a fraction exceeds the numerator by 5. If 3 be added to both, the fraction becomes 3/4. Find the fraction.
Answer :
Step 1 :
In this problem, the denominator of the fraction is linked to the value in the numerator.
That is, the denominator of a fraction exceeds the numerator by 5
Once we get the value of the numerator, easily we can get the value of the denominator and find the required fraction.
Step 2 :
Let x be the numerator.
Then, the denominator of the fraction is (x + 5).
Therefore, the required fraction is
= x / (x + 5) -----(1)
Step 3 :
It is given that if 3 be added to both, the fraction becomes 3/4.
Then, we have
(x + 3) / (x + 5 + 3) = 3 / 4
Simplify and solve fore x.
(x + 3) / (x + 8) = 3/4
4(x + 3) = 3(x + 8)
4x + 12 = 3x + 24
x = 12
Step 4 :
Substitute 12 for x in (1)
(1)-----> x / (x + 5) = 12 / (12 + 5)
x / (x + 5) = 12 / 17
So, the required fraction is 12 / 17.
Topic Wise Word Problems in Algebra
Please click on the topics given below in which you would like to have word problems.
Word problems on simple equations
Word problems on linear equations
Word problems on quadratic equations
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WORD PROBLEMS
Word problems on simple equations
Word problems on linear equations
Word problems on quadratic equations
Area and perimeter word problems
Word problems on direct variation and inverse variation
Word problems on comparing rates
Converting customary units word problems
Converting metric units word problems
Word problems on simple interest
Word problems on compound interest
Word problems on types of angles
Complementary and supplementary angles word problems
Trigonometry word problems
Markup and markdown word problems
Word problems on mixed fractrions
One step equation word problems
Linear inequalities word problems
Ratio and proportion word problems
Word problems on sets and venn diagrams
Pythagorean theorem word problems
Percent of a number word problems
Word problems on constant speed
Word problems on average speed
Word problems on sum of the angles of a triangle is 180 degree
OTHER TOPICS
Time, speed and distance shortcuts
Ratio and proportion shortcuts
Domain and range of rational functions
Domain and range of rational functions with holes
Graphing rational functions with holes
Converting repeating decimals in to fractions
Decimal representation of rational numbers
Finding square root using long division
L.C.M method to solve time and work problems
Translating the word problems in to algebraic expressions
Remainder when 2 power 256 is divided by 17
Remainder when 17 power 23 is divided by 16
Sum of all three digit numbers divisible by 6
Sum of all three digit numbers divisible by 7
Sum of all three digit numbers divisible by 8
Sum of all three digit numbers formed using 1, 3, 4
Sum of all three four digit numbers formed with non zero digits
Sum of all three four digit numbers formed using 0, 1, 2, 3
Sum of all three four digit numbers formed using 1, 2, 5, 6
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