**SHSAT Practice Questions and Answers in Math**

Here we are going to see some practice questions questions for SHSAT exams.

SHSAT Practice Questions and Answers in Math

**Question 11 :**

Express 6.925 x 10^{5} in standard form.

**Solution : **

= 6.925 x 10^{5}

= 6.925 x 100000

= 692500

**Question 12 :**

On the number line above, X is located at -10, Y is at -2, and Z is at 8. M (not shown) is the midpoint of XY, and N (not shown) is the midpoint of YZ. What is the midpoint of MN?

**Solution :**

Y is located at -2 and X is located at -10.

Numbers between X and Y are

-2, -3, -4, -5, -6, -7, -8, -9, -10

The midpoint of these two numbers is -6.

So, M is located at -6.

Numbers between Y and Z are

-2, -1, 0, 1, 2, 3, 4, 5, 6, 7, 8

So, N is located at 3.

Now, let us write the numbers between -6 and 3.

-6, -5, -4, -3, -2, -1, 0, 1, 2, 3

-1.5 is the midpoint of MN.

**Question 13 :**

If 0 < y < 1, which of the following statements must be true?

(A) y^{2} > y^{3} (B) y > 0.5y (C) y > y^{3}

(D) All of the above (E) None of the above

**Solution :**

Let x = 0.5

By applying the value of y in option A, we get

0.25 > 0.125 True

By applying the value of y in option B, we get

0.5 > 0.5 (0.5)

0.5 > 0.25 True

By applying the value of y in option C, we get

0.5 > (0.5)^{3}

0.5 > 0.125 True

Hence all of the above is true.

**Question 14 :**

The area of the square ABCD is 4 times larger than the area of square WXYZ. If the area of square WXYZ is 9, what is the difference between the length of a side of square ABCD and the length of a side of square WXYZ?

**Solution :**

Area of the square ABCD = 4 Area of the square WXYZ

Area of the square WXYZ = 9

a^{2} = 9

a = 3

Side length of square WXYZ = 3

Area of the square ABCD = 4(9) = 36

s^{2} = 36

s = 6

Difference between side length of ABCD and WXYZ

= 6 - 3

= 3

**Question 15 :**

Triangle GHI is similar to Triangle JKL.

What is the length of side JK?

**Solution :**

Since the above triangles are similar, the length of the sides are in the same ratio.

GI/JL = GH/JK = IH/ LK

(3x/4)/x = 12/JK = IH/LK

3/4 = 12/JK

JK = 12(4)/3

JK = 16

**Question 16 :**

Wesley and two of his friends are driving cross country nonstop and have agreed to take turns driving in 7-hours shifts. Each person will drive for one shift, and take two shifts off to rest. If Wesleyâ€™s first shift starts at 6:00 a.m., at what time will Wesley complete his third shift?

**Solution :**

1st shift 6 AM - 1 PM 1 PM - 8 PM 8 PM - 3 AM |
2nd shift 3 AM - 10 AM 10 AM - 5 PM 5 PM - 12 AM |
3rd shift 12 AM - 7 AM |

Hence the required answer is 7 : 00 AM.

**Question 17 :**

What is the difference between the largest and lowest integer in the sequence of consecutive odd integers whose sum is 15 ?

**Solution :**

Let us select three numbers 3, 5 and 7.

3 + 5 + 7 = 15

Difference between largest and lowest integer

= 7 - 3

= 4

Hence the answer is 4.

**Question 18 :**

The half life of a substance is the time it takes for a substance to decrease to half its initial amount. John has a pile of goo that decreases in amount at a constant rate. If John initially had 100 pounds of goo, and ten days later, he only had 25 pounds of goo, what is the half of the goo ?

**Solution :**

In 10 days, the goo decreased by 2 half lives. So each life is 5 days.

**Question 19 :**

What is the value of (9^{4} - 8^{4})/(9^{2} + 8^{2}) ?

**Solution :**

(9^{4} - 8^{4})/(9^{2} + 8^{2}) = [(9^{2})^{2} - (8^{2})^{2}]/(9^{2} + 8^{2})

= [((9^{2}) + (8^{2})) ((9^{2}) - (8^{2}))]/(9^{2} + 8^{2})

= 9^{2} - 8^{2}

= 81 - 64

= 17

Hence the answer is 17.

**Question 20 :**

Jackie fills a jug with water continuously. It takes her 2 minutes to fill up 50% of the empty space in the jug with water. After every 2 minutes, she puts a penny into a jar to celebrate. How many pennies will she have in the jar at the instant the jug has less than 30% empty space left ?

**Solution :**

Now Jackie starts to fill the jug. At the first round, he fills 50% of empty space in the jug in 2 minutes and drop a penny.

Now the jug contains 50% of empty space. If the fills half of the 50% of empty space at that instant, the quantity of water will become 75%. Hence the condition will not satisfy, by filling water in the second round.

So, there is only 1 penny in the jar at the instant the jug has lesser than 30% of empty space.

SHSAT Practice Questions and Answers in Math

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