**SHSAT Practice Questions and Answers in Math**

Here we are going to see some practice questions questions for SHSAT exams.

SHSAT Practice Questions and Answers in Math

**Question 11 :**

Express 6.925 x 10^{5} in standard form.

**Solution : **

= 6.925 x 10^{5}

= 6.925 x 100000

= 692500

**Question 12 :**

On the number line above, X is located at -10, Y is at -2, and Z is at 8. M (not shown) is the midpoint of XY, and N (not shown) is the midpoint of YZ. What is the midpoint of MN?

**Solution :**

Y is located at -2 and X is located at -10.

Numbers between X and Y are

-2, -3, -4, -5, -6, -7, -8, -9, -10

The midpoint of these two numbers is -6.

So, M is located at -6.

Numbers between Y and Z are

-2, -1, 0, 1, 2, 3, 4, 5, 6, 7, 8

So, N is located at 3.

Now, let us write the numbers between -6 and 3.

-6, -5, -4, -3, -2, -1, 0, 1, 2, 3

-1.5 is the midpoint of MN.

**Question 13 :**

If 0 < y < 1, which of the following statements must be true?

(A) y^{2} > y^{3} (B) y > 0.5y (C) y > y^{3}

(D) All of the above (E) None of the above

**Solution :**

Let x = 0.5

By applying the value of y in option A, we get

0.25 > 0.125 True

By applying the value of y in option B, we get

0.5 > 0.5 (0.5)

0.5 > 0.25 True

By applying the value of y in option C, we get

0.5 > (0.5)^{3}

0.5 > 0.125 True

Hence all of the above is true.

**Question 14 :**

The area of the square ABCD is 4 times larger than the area of square WXYZ. If the area of square WXYZ is 9, what is the difference between the length of a side of square ABCD and the length of a side of square WXYZ?

**Solution :**

Area of the square ABCD = 4 Area of the square WXYZ

Area of the square WXYZ = 9

a^{2} = 9

a = 3

Side length of square WXYZ = 3

Area of the square ABCD = 4(9) = 36

s^{2} = 36

s = 6

Difference between side length of ABCD and WXYZ

= 6 - 3

= 3

**Question 15 :**

Triangle GHI is similar to Triangle JKL.

What is the length of side JK?

**Solution :**

Since the above triangles are similar, the length of the sides are in the same ratio.

GI/JL = GH/JK = IH/ LK

(3x/4)/x = 12/JK = IH/LK

3/4 = 12/JK

JK = 12(4)/3

JK = 16

**Question 16 :**

Wesley and two of his friends are driving cross country nonstop and have agreed to take turns driving in 7-hours shifts. Each person will drive for one shift, and take two shifts off to rest. If Wesley’s first shift starts at 6:00 a.m., at what time will Wesley complete his third shift?

**Solution :**

1st shift 6 AM - 1 PM 1 PM - 8 PM 8 PM - 3 AM |
2nd shift 3 AM - 10 AM 10 AM - 5 PM 5 PM - 12 AM |
3rd shift 12 AM - 7 AM |

Hence the required answer is 7 : 00 AM.

**Question 17 :**

What is the difference between the largest and lowest integer in the sequence of consecutive odd integers whose sum is 15 ?

**Solution :**

Let us select three numbers 3, 5 and 7.

3 + 5 + 7 = 15

Difference between largest and lowest integer

= 7 - 3

= 4

Hence the answer is 4.

**Question 18 :**

The half life of a substance is the time it takes for a substance to decrease to half its initial amount. John has a pile of goo that decreases in amount at a constant rate. If John initially had 100 pounds of goo, and ten days later, he only had 25 pounds of goo, what is the half of the goo ?

**Solution :**

In 10 days, the goo decreased by 2 half lives. So each life is 5 days.

**Question 19 :**

What is the value of (9^{4} - 8^{4})/(9^{2} + 8^{2}) ?

**Solution :**

(9^{4} - 8^{4})/(9^{2} + 8^{2}) = [(9^{2})^{2} - (8^{2})^{2}]/(9^{2} + 8^{2})

= [((9^{2}) + (8^{2})) ((9^{2}) - (8^{2}))]/(9^{2} + 8^{2})

= 9^{2} - 8^{2}

= 81 - 64

= 17

Hence the answer is 17.

**Question 20 :**

Jackie fills a jug with water continuously. It takes her 2 minutes to fill up 50% of the empty space in the jug with water. After every 2 minutes, she puts a penny into a jar to celebrate. How many pennies will she have in the jar at the instant the jug has less than 30% empty space left ?

**Solution :**

Now Jackie starts to fill the jug. At the first round, he fills 50% of empty space in the jug in 2 minutes and drop a penny.

Now the jug contains 50% of empty space. If the fills half of the 50% of empty space at that instant, the quantity of water will become 75%. Hence the condition will not satisfy, by filling water in the second round.

So, there is only 1 penny in the jar at the instant the jug has lesser than 30% of empty space.

SHSAT Practice Questions and Answers in Math

After having gone through the stuff given above, we hope that the students would have understood, "SHSAT Practice Questions and Answers in Math".

Apart from the stuff given in this section "SHSAT Practice Questions and Answers in Math", if you need any other stuff in math, please use our google custom search here.

HTML Comment Box is loading comments...

**WORD PROBLEMS**

**HCF and LCM word problems**

**Word problems on simple equations **

**Word problems on linear equations **

**Word problems on quadratic equations**

**Area and perimeter word problems**

**Word problems on direct variation and inverse variation **

**Word problems on comparing rates**

**Converting customary units word problems **

**Converting metric units word problems**

**Word problems on simple interest**

**Word problems on compound interest**

**Word problems on types of angles **

**Complementary and supplementary angles word problems**

**Markup and markdown word problems **

**Word problems on mixed fractrions**

**One step equation word problems**

**Linear inequalities word problems**

**Ratio and proportion word problems**

**Word problems on sets and venn diagrams**

**Pythagorean theorem word problems**

**Percent of a number word problems**

**Word problems on constant speed**

**Word problems on average speed **

**Word problems on sum of the angles of a triangle is 180 degree**

**OTHER TOPICS **

**Time, speed and distance shortcuts**

**Ratio and proportion shortcuts**

**Domain and range of rational functions**

**Domain and range of rational functions with holes**

**Graphing rational functions with holes**

**Converting repeating decimals in to fractions**

**Decimal representation of rational numbers**

**Finding square root using long division**

**L.C.M method to solve time and work problems**

**Translating the word problems in to algebraic expressions**

**Remainder when 2 power 256 is divided by 17**

**Remainder when 17 power 23 is divided by 16**

**Sum of all three digit numbers divisible by 6**

**Sum of all three digit numbers divisible by 7**

**Sum of all three digit numbers divisible by 8**

**Sum of all three digit numbers formed using 1, 3, 4**

**Sum of all three four digit numbers formed with non zero digits**