**SHSAT Math Sample Test Questions**

Here we are going to see some practice questions questions for SHSAT exams.

**Question 1 :**

If p = -3 and q = 2, what is the value of p^{2} – (q – p)?

**Solution :**

Given statement :

= p^{2} – (q – p)

By applying the value of p and q in the above expression, we get

= (-3)^{2} – (2 – (-3))

= 9 – (2 + 3)

= 9 - 5

= 4

**Question 2 :**

What is the area of triangle ABC?

**Solution :**

= (1/2) [(30 + 6 + 84) - (24 + 21 + 30)]

= (1/2)[120 - 75]

= (1/2) (45)

= 22.5

Hence the answer is 22 ½ square units.

**Question 3 :**

If (64/(x-8)) + 7 = 11, what is the value of (64/(x-8)) ?

**Solution :**

**(64/(x-8)) + 7 = 11**

**Subtract 7 on both sides**

**(64/(x-8)) = 11 - 7**

**(64/(x-8)) = 4 **

**Hence the value of ****(64/(x-8)) is 4 .**

**Question 4 :**

If the diameter of a circle is 6.4 x 10^{8}, then the radius of
the circle is

**Solution :**

Diameter of a circle = 6.4 x 10^{8}

Radius of the circle = (6.4 x 10^{8} )/2

= 3.2 x 10^{8}

Hence the radius of the circle is 3.2 x 10^{8}.

**Question 5 :**

When 1/11 is expressed as a decimal, what
digit appears in the 16^{th} place to the right of the decimal point?

**Solution :**

1/11 = 0.0909.....

The number at the 4th place is 9, since 16 is the multiple of 4, 9 will appear in the 16th place.

**Question 6 :**

(7)(6) – 6 =

**Solution :**

= (7)(6) – 6

= 42 - 6

= 36

Hence the answer is 36.

**Question 7 :**

Fred and Michael collected money for the school trip. Fred collected 50% more than Michael. If Michael collected $150, how much did Fred and Michael collect all together?

**Solution :**

Let "x" be the money collected by Michael.

Money collected by Fred = x + 50% of x

= x + x/2

= 3x/2

Michael collected $150

Money collected by Fred = 3(150)/2

= 3(75)

= 225

Money collected by Fred and Michael = 150 + 225

= $375

**Question 8 :**

5.835 x 10^{4 }is equal to

**Solution :**

= 5.835 x 10^{4}

Since we have positive power, we have to move the decimal 4 digits to the right side.

= 58350

Hence the answer is 58350.

**Question 9 :**

What is the value of |x - y| + |y – x| if x = 9 and y = 2x?

**Solution :**

**|x - y| + |y – x| if x = 9 and y = 2x**

**y = 2x**

By applying the value of x, we get the value of y.

y = 2(9) = 18

**= |x - y| + |y – x| **

**= ****|9 - 18| + |18 – 9| **

**= |-9| + |9|**

**= 9 + 9**

**= 18**

**Hence the answer is 18.**

**Question 10 :**

When 54 is divided by the positive integer N, the quotient is 13 and the remainder is R. The value of R is

**Solution :**

Division algorithm :

Dividend = Divisor ⋅ quotient + Remainder

54 = N ⋅ 13 + R

13 (4) = 52

By dividing 54 by 4, we get 13 as quotient and 2 as remainder.

Hence the required remainder is 2.

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