SHSAT MATH SAMPLE TEST QUESTIONS

Question 1 :

If p = -3 and q = 2, what is the value of p² – (q – p)?

Solution :

Given statement :

=  p² – (q – p)

By  applying the value of p and q in the above expression, we get

  =  (-3)² – (2 – (-3))

  =  9 – (2 + 3)

  =  9 - 5

  =  4

Question 2 :

What is the area of triangle ABC?

Solution :

  =  (1/2) [(30 + 6 + 84) - (24 + 21 + 30)]

  =  (1/2)[120 - 75]

  =  (1/2) (45)

  =  22.5 

Hence the answer is 22 ½ square units.

Question 3 :

If (64/(x-8)) + 7 = 11, what is the value of (64/(x-8)) ?

Solution :

(64/(x-8)) + 7 = 11

Subtract 7 on both sides

(64/(x-8)) = 11 - 7

(64/(x-8))  =  4 

Hence the value of (64/(x-8)) is 4 .

Question 4 :

If the diameter of a circle is 6.4 x 10⁸, then the radius of the circle is

Solution :

Diameter of a circle = 6.4 x 10⁸

Radius of the circle  =  (6.4 x 10⁸ )/2

  =  3.2 x 10⁸

Hence the radius of the circle is 3.2 x 10⁸.

Question 5 :

When 1/11 is expressed as a decimal, what digit appears in the 16^th place to the right of the decimal point?

Solution :

1/11  =  0.0909.....

The number at the 4th place is 9, since 16 is the multiple of 4, 9 will appear in the 16th place.

Question 6 :

 (7)(6) – 6 =

Solution :

  =   (7)(6) – 6

  =  42 - 6

  =  36

Hence the answer is 36.

Question 7 :

Fred and Michael collected money for the school trip.  Fred collected 50% more than Michael.  If Michael collected $150, how much did Fred and Michael collect all together?

Solution :

Let "x" be the money collected by Michael.

Money collected by Fred  =  x + 50% of x

  =  x + (x/2)

  =  3x/2

Michael collected $150

Money collected by Fred  =  3(150)/2 

  =  3(75)

  =  225

Money collected by Fred and Michael  =  150 + 225

  =  $375

Question 8 :

5.835 x 10⁴ is equal to

Solution :

=  5.835 x 10⁴

Since we have positive power, we have to move the decimal 4 digits to the right side.

  =  58350

Hence the answer is 58350.

Question 9 :

What is the value of |x - y| + |y – x| if x = 9 and y = 2x?

Solution :

|x - y| + |y – x| if x = 9 and y = 2x

y = 2x

By applying the value of x, we get the value of y.

y  =  2(9)  =  18

=  |x - y| + |y – x| 

=  |9 - 18| + |18 – 9| 

=  |-9| + |9|

=  9 + 9

=  18

Hence the answer is 18.

Question 10 :

When 54 is divided by the  positive integer N, the quotient is 13 and the remainder is R.  The value of R is

Solution :

Division algorithm :

Dividend  =  Divisor ⋅ quotient + Remainder

54  =  N ⋅ 13 + R

13 (4)  =  52

By dividing 54 by 4, we get 13 as quotient and 2 as remainder.

Hence the required remainder is 2.

More Practice Test Papers

SHSAT math practice test - Paper 1

SHSAT math practice test - Paper 2

SHSAT math practice test - Paper 3

SHSAT math practice test - Paper 4

SHSAT math practice test - Paper 5

SHSAT math practice test - Paper 6

SHSAT math practice test - Paper 7

SHSAT math practice test - Paper 8

SHSAT math practice test - Paper 9

SHSAT math practice test - Paper 10

SHSAT math practice test - Paper 11

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