Writing expressions worksheet 6th grade :
A variable is a letter or symbol used to represent an unknown or unspecified number. The value of a variable may change.
The variables can take different values; they have no fixed value. But they are numbers. That is why as in the case of numbers, operations of addition, subtraction, multiplication and division can be done on them.
One important point must be noted regarding the expressions containing variables.
A number expression like (4 × 3) + 5 can be immediately evaluated as (4 × 3) + 5 = 12 + 5 = 17
But an expression like (4x + 5), which contains the variable x, cannot be evaluated. Only if x is given some value, an expression like (4x + 5) can be evaluated.
Let us see some example problems to understand how to write variable expressions.
Example 1 :
12 subtracted from z
Solution :
To form variable expression for the given statement we need to use the binary operator "-".
We need to subtract "12" from "z"
Example 2 :
25 added to r
Solution :
To form variable expression for the given statement we need to use the binary operator "+".
We need to add "25" with "r"
Hence the variable expression for the given statement is "25 + r"
Example 3 :
p multiplied by 16
Solution :
To form variable expression for the given statement we need to use the binary operator "x".
We need to multiply p by 16
Hence the variable expression for the given statement is "16p"
Example 4 :
y multiplied by 10 and then 7 added to the product
Solution :
To form variable expression for the given statement we need to use the binary operators "x" and "+".
y multiplied by 10 = y x 10 = 10 y
7 added to the product = 10 y + 7
Example 5 :
n multiplied by 2 and 1 subtracted from the product
Solution :
To form variable expression for the given statement we need to use the binary operators "x" and "-".
n multiplied by 2 = n x 2 = 2 n
1 subtracted from the product = 2 n - 1
Example 6 :
– p multiplied by 5
Solution :
To form variable expression for the given statement we need to use the binary operator "x".
– p multiplied by 5 = -p x 5 = -5p
Example 7 :
11 added to 2m
Solution :
To form variable expression for the given statement we need to use the binary operator "+".
11 added to 2m = 2m + 11
Example 8 :
5 times y to which 3 is added
Solution :
To form variable expression for the given statement we need to use the binary operators "x" and "+".
5 times y = 5 y
to which 3 is added = 5y + 3
Example 9 :
5 times y from which 3 is subtracted
Solution :
To form variable expression for the given statement we need to use the binary operators "x" and "-".
5 times y = 5 y
which 3 is subtracted = 5y - 3
Example 10 :
y is multiplied by – 8 and then 5 is added to the result
Solution :
To form variable expression for the given statement we need to use the binary operators "x" and "+".
y is multiplied by – 8 = -8 y
5 is added to the result = -8y + 5
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WORD PROBLEMS
HCF and LCM word problems
Word problems on simple equations
Word problems on linear equations
Word problems on quadratic equations
Area and perimeter word problems
Word problems on direct variation and inverse variation
Word problems on comparing rates
Converting customary units word problems
Converting metric units word problems
Word problems on simple interest
Word problems on compound interest
Word problems on types of angles
Complementary and supplementary angles word problems
Markup and markdown word problems
Word problems on mixed fractrions
One step equation word problems
Linear inequalities word problems
Ratio and proportion word problems
Word problems on sets and venn diagrams
Pythagorean theorem word problems
Percent of a number word problems
Word problems on constant speed
Word problems on average speed
Word problems on sum of the angles of a triangle is 180 degree
OTHER TOPICS
Time, speed and distance shortcuts
Ratio and proportion shortcuts
Domain and range of rational functions
Domain and range of rational functions with holes
Graphing rational functions with holes
Converting repeating decimals in to fractions
Decimal representation of rational numbers
Finding square root using long division
L.C.M method to solve time and work problems
Translating the word problems in to algebraic expressions
Remainder when 2 power 256 is divided by 17
Remainder when 17 power 23 is divided by 16
Sum of all three digit numbers divisible by 6
Sum of all three digit numbers divisible by 7
Sum of all three digit numbers divisible by 8
Sum of all three digit numbers formed using 1, 3, 4
Sum of all three four digit numbers formed with non zero digits