# WRITING DIRECT VARIATION EQUATIONS WORKSHEET

## About "Writing direct variation equations worksheet"

Writing direct variation equations worksheet :

Here we are going to see some practice questions on writing direct variation equations.

## Writing direct variation equations worksheet - Practice questions

(1)  In a direct variation y = 12 when x = 2. Write the direct variation equation that shows the relationship between x and y.

(2)  In a direct variation y = 300 when x = 5. Write the direct variation equation that shows the relationship between x and y.

(3)  In a direct variation y = 12 when x = 40. Write the direct variation equation that shows the relationship between x and y.

(4)  In a direct variation y = 4 when x = 15. Write the direct variation equation that shows the relationship between x and y.

(5)  In a direct variation y = 48 when x = 16. Write the direct variation equation that shows the relationship between x and y.

## Writing direct variation equations worksheet - Solution

Question 1 :

In a direct variation y = 12 when x = 2. Write the direct variation equation that shows the relationship between x and y .

Solution :

Equation of direct variation :

y = kx  ---------(1)

In order to find the value of "k" in the equation, we need to apply the values of x and y in the equation.

12  =  k (2)

12  =  2k

Divide by 2 on both sides

12/2  = 2k/2

6  =  k

k  =  6

By applying the value of k in the (1)st equation, we get

y = 6x

Hence the required equation is y = 6x.

Question 2 :

In a direct variation y = 300 when x = 5. Write the direct variation equation that shows the relationship between x and y .

Solution :

Equation of direct variation :

y = kx  ---------(1)

In order to find the value of "k" in the equation, we need to apply the values of x and y in the equation.

300  =  k (5)

300  =  5k

Divide by 5 on both sides

300/5  = 5k/5

60  =  k

k  =  60

By applying the value of k in the (1)st equation, we get

y = 60x

Hence the required equation is y = 60x.

Question 3 :

In a direct variation y = 12 when x = 40. Write the direct variation equation that shows the relationship between x and y .

Solution :

Equation of direct variation :

y = kx  ---------(1)

In order to find the value of "k" in the equation, we need to apply the values of x and y in the equation.

40  =  k (12)

40  =  12k

Divide by 12 on both sides

40/12  = 12k/12

10/3  =  k

k  =  10/3

By applying the value of k in the (1)st equation, we get

y = (10/3)x

Hence the required equation is y = 10x/3.

Question 4 :

In a direct variation y = 4 when x = 15. Write the direct variation equation that shows the relationship between x and y .

Solution :

Equation of direct variation :

y = kx  ---------(1)

In order to find the value of "k" in the equation, we need to apply the values of x and y in the equation.

4  =  k (15)

4  =  15k

Divide by 15 on both sides

4/15  = 15k/15

4/15  =  k

k  =  4/15

By applying the value of k in the (1)st equation, we get

y = (4/15)x

Hence the required equation is y = 4x/15.

Question 5 :

In a direct variation y = 48 when x = 16. Write the direct variation equation that shows the relationship between x and y .

Solution :

Equation of direct variation :

y = kx  ---------(1)

In order to find the value of "k" in the equation, we need to apply the values of x and y in the equation.

48  =  k (16)

48  =  16k

Divide by 16 on both sides

48/16  = 16k/16

3  =  k

k  =  3

By applying the value of k in the (1)st equation, we get

y = 3x

Hence the required equation is y = 3x.

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