# WRITE EQUATIONS FOR PROPORTIONAL RELATIONSHIPS FROM TABLES

Two variables have a proportional relationship if the ratio of one variable to the other is constant.

A proportional relationship between x and y can be modeled by the equation y  =  kx.

Example 1 :

Determine the constant of proportionality for each table and also write an equation for the relationship between x and y. Solution :

To find the constant of proportionality, we have to divide y by x.

Ratio of y to x :

30/3  =  10

80/8  =  10

100/10  =  10

60/6  =  10

70/7  =  10

The ratio for each pair of x- and y-values is 10. So, the variables have a proportional relationship.

So, every concrete block weighs 10 kilograms. A proportional relationship between x and y can be modeled by the equation y  =  kx.

Here the value of k is 10.

So, the required equation for the relationship between x and y is y = 10x.

Example 2 :

Determine the constant of proportionality for each table. Solution :

To find the constant of proportionality, we have to divide y by x.

Ratio of y to x :

15/5  =  3

30/10  =  3

18/6  =  3

27/9  =  3

6/2  =  3

The ratio for each pair of x- and y-values is 3. So, the variables have a proportional relationship.

So, every can of paint you could paint 3 bird houses.

A proportional relationship between x and y can be modeled by the equation y = kx.

Here the value of k is 3.

So, the required equation for the relationship between x and y is y = 3x.

Example 3 :

Determine the constant of proportionality for each table. Solution :

To find the constant of proportionality, we have to divide y by x.

Ratio of y to x :

342/9  =  38

266/7  =  38

228/6  =  38

304/8  =  38

114/3  =  38

The ratio for each pair of x- and y-values is 38. So, the variables have a proportional relationship.

So, every vote for Faye there were 38 votes for Victor.

A proportional relationship between x and y can be modeled by the equation y = kx.

Here the value of k is 38.

So, the required equation for the relationship between x and y is y = 38x.

Example 4 :

Determine the constant of proportionality for each table. Solution :

To find the constant of proportionality, we have to divide y by x.

Ratio of y to x :

1212/6  =  202

808/4  =  202

2020/10  =  202

606/3  =  202

1616/8  =  202

The ratio for each pair of x- and y-values is 202. So, the variables have a proportional relationship.

So,every chocolate bar has 202 calories.

A proportional relationship between x and y can be modeled by the equation y = kx.

Here the value of k is 202.

So, the required equation for the relationship between x and y is y = 202x.

Example 5 :

Determine the constant of proportionality for each table. Solution :

To find the constant of proportionality, we have to divide y by x.

Ratio of y to x :

14/7  =  2

16/8  =  2

12/6  =  2

20/10  =  2

4/2  =  2

The ratio for each pair of x- and y-values is 2. So, the variables have a proportional relationship.

For each piece of chicken it costs 2 dollars.

A proportional relationship between x and y can be modeled by the equation y = kx.

Here the value of k is 2.

So, the required equation for the relationship between x and y is y = 2x.

Example 6 :

Determine the constant of proportionality for each table. Solution :

To find the constant of proportionality, we have to divide y by x.

Ratio of y to x :

32/2  =  16

80/5  =  16

144/9  =  16

112/7  =  16

160/10  =  16

The ratio for each pair of x- and y-values is 16. So, the variables have a proportional relationship.

For every box of candy you get 16 pieces.

A proportional relationship between x and y can be modeled by the equation y = kx.

Here the value of k is 16.

So, the required equation for the relationship between x and y is y = 16x. Apart from the stuff given above, if you need any other stuff in math, please use our google custom search here.

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