# WORKSHEET ON WORD PROBLEMS ON RATIONAL NUMBERS

Problem 1 :

John reads 1/3 part of a book in 1 hour. How much part of the book will he read in 2  1/5 hours?

Problem 2 :

A teacher wants to give pizza to her students and each student can eat 1/4 of a pizza. If there are 25 students in her class, how many pizzas does she need ?

Problem 3 :

Mason made 3/4 of a pound of trail mix. If he puts 3/8 of a pound into each bag, how many bags can Mason fill?

Problem 4 :

A shop keeper sold 7  3/4 kg, 2  1/2 kg and 3  3/5 kg of sugar to three customers in a day.Find the total weight of sugar on that day?

Problem 5 :

John bought 25 kg of Rice and he used 1 3/4 kg on the first day, 4 1/2 kg on the second day. Find the remaining quantity of rice left. ## Solutions

Problem 1 :

John reads 1/3 part of a book in 1 hour. How much part of the book will he read in 2  1/5 hours?

Solution :

The part of the book read by John in 1 hour = 1/3

So, the part of the book read by him in 2  1/5 hours

=  2  1/5  x (1/3)

=  (11/5) x (1/3)

=  11/15

Problem 2 :

A teacher wants to give pizza to her students and each student can eat 1/4 of a pizza. If there are 25 students in her class, how many pizzas does she need ?

Solution :

To find how many pizzas needed, we have to divide 25 by 1/4.

Step 1 :

Take the reciprocal of the divisor 1/4.

1/4 ---- reciprocal ----> 4

Step 2 :

Multiply 25 by 4

(25) x (4)  =  100

So, the teacher needs 100 pizzas.

Problem 3 :

Mason made 3/4 of a pound of trail mix. If he puts 3/8 of a pound into each bag, how many bags can Mason fill?

Solution :

To find the number of bags, we have to divide 3/4 by 3/8.

Step 1 :

Take the reciprocal of the divisor 3/8.

3/8 ---- reciprocal ----> 8/3

Step 2 :

Multiply 3/4 by 8/3

(3/4) x (8/3)

Step 3 : Simplify

(1/1) x (2/1)

Step 4 : Multiply

(1/1) x (2/1)  =  2

So, Mason fill can fill the trail mix in 2 bags.

Problem 4 :

A shop keeper sold 7  3/4 kg, 2  1/2 kg and 3  3/5 kg of sugar to three customers in a day.Find the total weight of sugar on that day?

Solution :

To find the total weight of sugar on that day, we have to add the above quantities.

Total weight of sugar  =  7  3/4 + 2  1/2 + 3  3/5

Converting the above mixed fractions as improper fractions, we get

=  (31/4) + (5/2) + (18/5)

Since the denominators of these two fractions are not same, we have to take L.C.M

L.C.M (4, 2, 5)  =  20

=  (31/4) x (5/5) + (5/2) x (10/10) + (18/5) x (4/4)

=  (155/20) + (50/20) + (72/20)

=  (155 + 50 + 72)/20

=  277/20

=  13  17/20

Hence the total weight of sugar sold  =  13  17/20 kg.

Problem 5 :

John bought 25 kg of Rice and he used 1 3/4 kg on the first day, 4 1/2 kg on the second day. Find the remaining quantity of rice left.

Solution :

Rice used on first day  =  1  3/4 kg

Rice used on second day  =  4  1/2 kg

Quantity of rice used on first and second day

=  (1  3/4) + (4  1/2)

Converting the above mixed fraction in to improper fraction, we get

=  7/4 + 9/2

=  7/4 + (9/2) x (2/2)

= 7/4 + 18/4

=  (7 + 18)/4

=  25/4

Remaining quantity of rice left  =   25 -  (25/4)

=  (100 - 25)/4

=  75/4

=  18  3/4 kg

Remaining quantity of rice  =  18  3/4 kg. Apart from the stuff given in this section, if you need any other stuff in math, please use our google custom search here.

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