# WORD PROBLEMS ON PROFIT AND LOSS

Problem 1 :

Cindy bought 50 pens for \$100. She then sold each pen for \$2.50. Find the profit or loss percentage.

Solution :

Cost price of 50 pens = \$100

Cost price of 1 pen = 100/50 = \$2

Selling price of 1 pen = \$2.50

Because the selling price of 1 pen is more than cost price of 1 pen, there is profit.

Finding Profit :

Profit = Selling price - Cost price

= 2.50 - 2

= 0.50

Finding Profit Percentage :

Profit % = (Profit/Cost price) ⋅ 100%

= (0.50/2) ⋅ 100%

= 25%

Problem 2 :

Jacob purchased a house for \$49,000. He spent \$6000 for repair and \$5,000 for air-conditioning. If he had sold the house \$58,000, find the gain or loss percentage in this transaction. (If it is needed, round your answer to the nearest hundredths)

Solution :

Total amount spent on the house is

= 49,000 + 6,000 + 5,000

= 60,000

This is the cost price of the house (\$60,000).

Selling price of the house = \$58,000.

Because the selling price of the house is less than the cost price, there is loss.

Finding Loss :

Loss = Cost price - Selling price

= 60,000 - 58,000

= 2,000

Finding Loss Percentage :

Loss % = (Loss/Cost price) ⋅ 100%

= (2000/60000) ⋅ 100%

= 3.33%

Problem 3 :

Goods are purchased for \$1500. If one fifth of the goods sold at a profit of 5% and the remaining four-fifth of the goods at a profit of 10%, find the net profit percentage.

Solution :

Cost price of one-fifth of the goods is

= 1/5 ⋅ 1500

= 300

Selling price of one-fifth of the goods (at 5% profit) is

= (100 + 5)% of 300

= 105% of 300

= 1.05 ⋅ 300

= 315

Cost price of remaining four-fifth of the goods is

= 4/5 ⋅ 1500

= 1,200

Selling price of the remaining four-fifth of the goods (at 10% profit) is

= (100 + 10)% of 1200

= 110% of 1200

= 1.10 ⋅ 1200

= 1,320

Selling price of the total goods :

= 315 + 1,320

= 1,635

Finding Net Profit :

Net profit = S.P of total goods - C.P of total goods

= 1635 - 1500

= 135

Finding Net Profit Percentage :

Net profit % = (Net profit/Cost price) ⋅ 100%

= (135/1500) ⋅ 100%

= 9%

Problem 4 :

A trader bought a product for \$200. If marks his goods 20% above the cost price and gives a discount of 10% for cash, find his profit percentage.

Solution :

Cost price of the product = \$100.

Marked price (20% above the cost price) is

= (100 + 20)% of 200

= 120% of 200

= 1.2 ⋅ 200

= 240

Selling price price is the price which is after 20% discount from the marked price.

So, the selling price is

= (100 - 10)% of Marked price

= 90% of 240

= 0.9 ⋅ 240

= 216

Finding Profit :

Profit = Selling price - Cost price

= 216 - 200

= 16

Finding Profit Percentage :

Profit % = (Profit/Cost price) ⋅ 100%

= (16/200) ⋅ 100%

= 8%

Problem 5 :

A person wants to get 20% profit after selling his object at 20% discount. Find the required percentage increase in marked price.

Solution :

Let the cost price be \$100.

Then, the selling price (at 20% profit) is

= (100 + 20)% of 100

= 120% of 100

= 1.2 ⋅ 100

= 120

Selling price is the price which is after 20% discount from the marked price.

It has been illustrated in the picture given below. From the above picture, we get

Selling price = (100 - 20)% of Marked price

120 = 80% of x

120 = 0.8x

Divide both sides by 0.8.

150 = x

So, the marked price is \$150.

Here,

Cost price = \$100

Marked Price = \$150

Hence, the required percentage increase is 50%.

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