WORD PROBLEMS ON PERCENTAGE
Word Problems on Percentage :
In this section, we are going to learn, how to solve percentage word problems step by step.
Before we look at the problems, if you want to know the shortcuts required for solving percentage problems,
Word problems on Percentage
Problem 1 :
John paid $64 for an item after 20% discount. Find the price of the item without discount.
Solution :
Let x be the price of the item without discount.
Given : John paid $64 for the item after 20% discount.
Then, we have
(100 - 20)% of x = 64
0.8x = 64
Divide each side by 0.8
x = 80
So, the price of the item without discount is $80.
Problem 2 :
If A's salary is 20% less than B's salary. By what percent is B's salary more than A's salary ?
Solution :
Let us assume B's salary = $100 ----------(1)
Then, A's salary = $80 --------(2)
Now we have to find the percentage increase from (2) to (1).
Difference between (1) and (2) = $ 20
Percentage increase from (2) to (1) is
= (20/80) ⋅ 100%
= 25%
Hence, B's salary is 25% more than A's salary.
Problem 3 :
In an election, a candidate who gets 84% of votes is elected by majority with 588 votes. What is the total number of votes polled ?
Solution :
Let "x" be the total number of votes polled.
Given : A candidate who gets 84% of votes is elected by majority of 476 votes
From the above information, we have
84% of x = 588 ---------> 0.84x = 588
x = 588 / 0.84
x = 700
Hence, the total number of votes polled 700.
Problem 4 :
When the price of a product was decreased by 10 % , the number sold increased by 30 %. What was the effect on the total revenue ?
Solution :
Before decrease in price and increase in sale,
Let us assume that price per unit = $100.
Let us assume that the number of units sold = 100
Then the total revenue = 100 ⋅ 100 = 10000 --------(1)
After decrease 10 % in price and increase 30 % in sale,
Price per unit = $ 90.
Number of units sold = 130
Then the total revenue = 90 ⋅ 130 = 11700 --------(2)
From (1) and (2), it is clear that the revenue is increased.
Difference between (1) and (2) = 1700
Percent increase in revenue is
= (Actual increase / Original revenue) ⋅ 100 %
= (1700/10000) ⋅ 100 %
= 17 %
Hence, the net effect in the total revenue is 17% increase.
Problem 5 :
A student multiplied a number by 3/5 instead of 5/3. What is the percentage error in the calculation ?
Solution :
In the given two fractions, the denominators are 5 and 3.
Let us assume a number which is divisible by both 5 and 3.
Least common multiple of (5, 3) = 15.
So, let the number be 15.
15 ⋅ 3/5 = 9 ----------(1) ---------incorrect
15 ⋅ 5/3 = 25 ---------(2) --------correct
Difference between (1) and (2) is 16
Percentage error is
= (Actual error/Correct answer) ⋅ 100 %
= (16 / 25) ⋅ 100 %
= 64%
Hence, the percentage error in the calculation is 64%.
Apart from the problems on percentage given above, if you need more problems on percentage, please click the following links.
After having gone through the stuff given above, we hope that the students would have understood, how to solve word problems on percentage.
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