# WORD PROBLEMS ON PERCENTAGE

Problem 1 :

John paid \$64 for an item after 20% discount. Find the price of the item without discount.

Solution :

Let x be the price of the item without discount.

Given : John paid \$64 for the item after 20% discount.

Then, we have

(100 - 20)% of x = 64

0.8x = 64

Divide each side by 0.8.

x = 80

So, the price of the item without discount is \$80.

Problem 2 :

If A's salary is  20% less than B's salary. By what percent is B's salary more than A's salary?

Solution :

Let us assume B's salary = \$100 ----(1)

Then, A's salary = \$80 ----(2)

Now we have to find the percentage increase from (2) to (1).

Difference between (1) and (2) = \$20.

Percentage increase from (2) to (1) is

= (20/80)  100%

= 25%

Hence,  B's salary is 25% more than A's salary.

Problem 3 :

In an election, a candidate who gets 84% of votes is elected by majority with 588 votes. What is the total number of votes polled?

Solution :

Let "x" be the total number of votes polled.

Given : A candidate who gets 84% of votes is elected by majority of 476 votes

From the above information, we have

84% of x = 588 ----> 0.84x = 588

x = 588/0.84

x = 700

Hence,  the total number of votes polled 700.

Problem 4 :

When the price of a product was decreased by 10 % , the number sold increased by 30 %. What was the effect on the total revenue?

Solution :

Before decrease in price and increase in sale,

Let us assume that price per unit = \$100.

Let us assume that the number of units sold = 100.

Then the total revenue = 100  100 = 10000 ----(1)

After decrease 10 % in price and increase 30 % in sale,

price per unit = \$90

number of units sold = 130

Then the total revenue = 90  130 = 11700 ----(2)

From (1) and (2), it is clear that the revenue is increased.

Difference between (1) and (2) = 1700.

Percent increase in revenue is

= (Actual increase/Original revenue)  100%

= (1700/10000)  100%

= 17 %

Hence,  the net effect in the total revenue is 17% increase.

Problem 5 :

A student multiplied a number by 3/5 instead of 5/3. What is the percentage error in the calculation?

Solution :

In the given two fractions, the denominators are 5 and 3.

Let us assume a number which is divisible by both 5 and 3.

Least common multiple of (5, 3) = 15.

So, let the number be 15.

15  3/5 = 9 ----(1) ----> incorrect

15  5/3 = 25 ----(2) ----> correct

Difference between (1) and (2) is 16.

Percentage error is

= (16 / 25)  100%

= 64%

Hence,  the percentage error in the calculation is 64%.

Kindly mail your feedback to v4formath@gmail.com

## Recent Articles

1. ### Algebraic Manipulation Worksheet

Jan 28, 23 08:20 AM

Algebraic Manipulation Worksheet

2. ### Algebraic Manipulation Problems

Jan 28, 23 08:18 AM

Algebraic Manipulation Problems