Problem 1 :
Raman’s age is three times he sum of the ages of his two sons. After 5 years his age will be twice the sum of the ages of his two sons. Find the age of Raman
Solution :
Let x be Raman's age and y be the sum of ages of his two sons.
x = 3y -----(1)
After 5 years :
Raman's age = x + 5
The sum of the ages of his two sons = y + 5 + 5
= y + 10
x + 5 = 2(y + 10)
x + 5 = 2y + 20
x - 2y = 20 - 5
x - 2y = 15 --------(2)
By applying the value of x in (2), we get
3y - 2y = 15
y = 15
x = 3(15)
x = 45
So, Raman is 45 years old.
Problem 2 :
The middle digit of a number between 100 and 1000 is zero and the sum of the other digit is 13. If the digits are reversed, the number so formed exceeds the original number by 495. Find the number
Solution :
The required number will be in the form X 0 Y
Middle digit = 0
x + y = 13 -------(1)
Y 0 X = X0Y + 495
100y + x = 100x + 1y + 495
x - 100x + 100y - y = 495
-99x + 99y = 495
-x + y = 5 -------(2)
x = y - 5
By applying the value of x in (1), we get
y - 5 + y = 13
2y = 13+5
2y = 18
y = 9
When y = 9,
x = 9 - 5
x = 4
So, the required number is 409.
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