In this page volume solution5 we are going to see solution of each questions of the worksheet volume worksheet2.

**Question 11**:

A vessel is in the form of frustum of a cone. Its radius at one end and the height are 8 cm and 14 cm respectively. If its volume is 5676/3 cm³,then find the radius at the other end.

**Solution:**

Volume of the frustum cone = (5676/3) cm³

Let "r" be the required radius

Radius (R) = 8 cm

height (h) = 14 cm

(1/3) Π h (R²+ r² + R r) = (5676/3)

(1/3) **x** (22/7)** x** (14) (8²+ r² + 8 r) = (5676/3)

(8²+ r² + 8 r) = (5676/3)**x **(3/1) **x** (7/22)** x** (1/14)

(64 + r² + 8 r) = (258)**x **(7)** x** (1/14)

(64 + r² + 8 r) = (258)**x **(1/2)

r² + 8 r + 64 = 129

r² + 8 r + 64 -129 = 0

r² + 8 r - 65 = 0

(r + 13) (r - 5) = 0

r + 13 = 0 r - 5 = 0

r = -13 r = 5 cm

**Therefore required radius = 5 cm**

**Question 12**:

The perimeter of the ends of a frustum of a cone are 44 cm and 8.4 Π cm. If the depth is 14 cm, then find its volume.

**Solution:**

Perimeter of upper end = 44 cm

Perimeter of lower end = 8.4 Π cm

Height of frustum cone =14 cm

Now we have to find the volume of frustum cone

Volume of the frustum cone = (1/3) Π h (R²+ r² + R r)

2 Π R = 44

2 **x** (22/7) **x** R = 44

R = 44 **x **(1/2) **x** (7/22)

R = 2 **x **(1/2) **x** (7)

R = 7

2 Π r = 8.4 Π

2 **x** Π **x** r = 8.4 Π

r = 8.4 Π **x **(1/2Π)

r = 4.2

Volume of the frustum cone = (1/3)** x** (22/7) **x** (14) (7²+ 4.2² + 7(4.2))

= (44/3) (49+ 29.4 + 17.64)

= (44/3) (96.04)

= (44) (32.013)

= 1408.57 cm³

**Volume of the frustum cone = 1408.57 cm³**

volume solution5 volume solution5

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