**Vertices of square question2 :**

Here we are going to see how to check whether the given points form a square

**Definition of square :**

Area enclosed by the 4 equal sides is called the area of the square.

(i) Plot the given points in the graph and draw the square.

(ii) Now we need to find the length of all sides.

(iii) In a square length of all sides are equal.

(iv) Length of diagonals are also equal

If we prove the above two conditions(iii, iv) are true, we can decide that the given points form a square.

**Question 2 :**

Examine whether the given points A (8,8) and B (13,-4) and C (1,-9) and D (-4,3) forms a square.

**Solution :**

**Solution :**

To show that the given points forms a square we need to find the distance between the given points.

Distance Between Two Points (x ₁, y₁) and (x₂ , y₂)

**√(x₂ - x₁)² + (y₂ - y₁)²**

Four points are A (8,8) and B (13,-4) and C (1,-9) and D (-4,3)

Distance between the points A and B

= **√(x₂ - x₁)² + (y₂ - y₁)²**

Here **x₁ = 8, y₁ = 8, x₂ = 13 and y₂ = -4**

**= **
√(13-8)² + (-4-8)²

= ** **
√(5)² + (-12)²

= ** **
√25 + 144

= √169

= 13 units

Distance between the points B and C

= **√(x₂ - x₁)² + (y₂ - y₁)²**

Here **x₁ = 13, y₁ = -4, x₂ = 1 and y₂ = -9**

**= **
√(1-13)² + (-9-(-4))²

= ** **
√(-12)² + (-9+4)²

= ** **
√144 + (-5)²

= √144 + 25

= √169

= 13 units

Distance between the points C and D

= **√(x₂ - x₁)² + (y₂ - y₁)²**

Here **x₁ = 1, y₁ = -9, x₂ = -4 and y₂ = 3**

**= **
√(-4-1)² + (3-(-9))²

= ** **
√(-5)² + (3+9)²

= ** **
√25 + 12²

= √25 + 144

= √169

= 13 units

Distance between the points D and A

= **√(x₂ - x₁)² + (y₂ - y₁)²**

Here **x₁ = -4, y₁ = 3, x₂ = 8 and y₂ = 8**

**= **
√(8-(-4))² + (8-3)²

= ** **
√(8+4)² + (5)²

= ** **
√12² + 5²

= √144 + 25

= √169

= 13 units

AB = 13 units

BC = 13 units

CD = 13 units

DA = 13 units

Length of opposite sides are equal.To test whether it forms right triangle we need to find the length of diagonal AC and BD.

Distance between the points A and C =

**√(x₂ - x₁)² + (y₂ - y₁)²**

Here **x₁ = 2, y₁ = 6, x₂ = 0 and y₂ = -2**

**= **
√(0-2)² + (-2-6)²

= ** **
√(-2)² + (-8)²

= ** **
√4 + 64

= √70 units

Distance between the points B and D

= **√(x₂ - x₁)² + (y₂ - y₁)²**

Here **x₁ = 5, y₁ = 1, x₂ = -3 and y₂ = 3**

**= **
√(-3-5)² + (3-1)²

= ** **
√(-8)² + (2)²

= ** **
√64 + 4

= √70 units

Length of all sides and diagonals are equal so the given vertices forms a square. Vertices of square question2

(1) Examine whether the given points A (2,6) and B (5,1) and C (0,-2) and D (-3,3) forms a square.

(2) Examine whether the given points A (8,8) and B (13,-4) and C (1,-9) and D (-4,3) forms a square.

(3) Examine whether the given points A (-2,2) and B (2,2) and C (2,-2) and D (-2,-2) forms a square.

(4) Examine whether the given points A (-9,-7) and B (-6,-7) and C (-6,-4) and D (-9,-4) forms a square.

(5) Examine whether the given points A (1,2) and B (2,2) and C (2,3) and D (1,3) forms a square.

(6) Examine whether the given points A (-1,-8) and B (4,-6) and C (2,-1) and D (-3,-3) forms a square.

(7) Examine whether the given points A (0,-1) and B (2,1) and C (0,3) and D (-2,1) forms a square.

- Solution for vertices of square question 1
- Solution for vertices of square question 2
- Solution for vertices of square question 3
- Solution for vertices of square question 4
- Solution for vertices of square question 5
- Solution for vertices of square question 6
- Solution for vertices of square question 7

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