**Vectors :**

A vector is a quantity that has both direction and magnitude, or size, and is represented by an arrow drawn between two points.

In this section, we will learn how to find the magnitude of a vector and the direction of a vector. We will also learn how to add vectors.

The magnitude of a vector AB is the distance from the initial point A to the terminal point B, and is written |AB|.

If a vector is drawn in a coordinate plane, we can use the Distance Formula to find its magnitude.

The initial and terminal points of the vector PQ are points P and Q. Draw PQ in a coordinate plane. Write the component form of the vector and find its magnitude.

(i) P(0, 0) and Q(-6, 3)

(ii) P(0, 2) and Q(5, 4)

(iii) P(3, 4) and Q(-2, -1)

**Solution : **

**Solution (i) : **

Component form = ⟨x_{2} - x_{1}, y_{2} - y_{1}⟩

Vector PQ = ⟨-6 - 0, 3 - 0⟩

Vector PQ = ⟨-6, 3⟩

We can use the distance formula to find the magnitude.

|PQ| = √[(-6 - 0)^{2} + (3 - 0)^{2}]

|PQ| = √45

|PQ| ≈ 6.7

**Solution (ii) : **

Component form = ⟨x_{2} - x_{1}, y_{2} - y_{1}⟩

Vector PQ = ⟨5 - 0, 4 - 2⟩

Vector PQ = ⟨5, 2⟩

We can use the distance formula to find the magnitude.

|PQ| = √[(5 - 0)^{2} + (4 - 2)^{2}]

|PQ| = √29

|PQ| ≈ 5.4

**Solution (iii) : **

Component form = ⟨x_{2} - x_{1}, y_{2} - y_{1}⟩

Vector PQ = ⟨-2 - 3, -1 - 4⟩

Vector PQ = ⟨-5, -5⟩

We can use the distance formula to find the magnitude.

|PQ| = √[(-2 - 3)^{2} + (-1 - 4)^{2}]

|PQ| = √50

|PQ| ≈ 7.1

The direction of a vector is determined by the angle it makes with a horizontal line. In real-life applications, the direction angle is described relative to the directions north, east, south, and west.

In a coordinate plane, the x-axis represents an east-west line. The y-axis represents a north-south line.

The vector AB describes the velocity of a moving ship. The scale on each axis is in miles per hour.

(i) Find the speed of the ship.

(ii) Find the direction it is travelling relative to east.

**Solution : **

**Solution (i) : **

The magnitude of the vector AB represents the speed of the ship.

We can use the distance formula to find the magnitude of the vector AB.

|AB| = √[(25 - 5)^{2} + (20 - 5)^{2}]

|AB| = √[20^{2} + 15^{2}]

|AB| = √[400 + 225]

|AB| = √625

|AB| = 25

The speed of the ship is 25 miles per hour.

**Solution (ii) : **

The tangent of the angle formed by the vector and a line drawn parallel to the x-axis is

15/20 or 0.75

We can use the calculator to find angle measure as shown below.

The ship is travelling in a direction about 37° north of east.

**Equal Vectors :**

Two vectors are equal, if they have the same magnitude and direction. They do not have to have the same initial and terminal points.

**Parallel Vectors :**

Two vectors are parallel, if they have the same or opposite directions.

In the diagram shown above, the vectors AB, CD and EF have same direction.

But only the vectors AB and CD are equal in length.

So, the following vectors are equal vectors.

AB and CD

And the following vectors are parallel vectors.

AB, CD, EF and HG

Two vectors can be added to form a new vector. To add the vectors u and v geometrically, place the initial point of the vector v on the terminal point of the vector u, (or place the initial point of the vector u on the terminal point of the vector v).

The sum is the vector that joins the initial point of the first vector and the terminal point of the second vector .

This method of adding vectors is often called the parallelogram rule because the sum vector is the diagonal of a parallelogram.

We can also add vectors algebraically.

Let the vector u = ⟨3, 5⟩ and the vector v = ⟨-6, -1⟩. To find the sum vector u + v, add the horizontal components and vertical components of the vectors u and v.

The sum vector is

u + v = ⟨3 + (-6), 5 + (-1)⟩

u + v = ⟨3 - 6, 5 - 1⟩

u + v = ⟨-3, 4⟩

After having gone through the stuff given above, we hope that the students would have understood, "Vectors".

Apart from the stuff given in this section, if you need any other stuff in math, please use our google custom search here.

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