USING PROPERTIES OF DEFINITE INTEGRALS

Problem 1 :

Evaluate the following integrals using properties of integration :

Solution :

Since the limit is 0 to 2π, we may use one of the properties.

If f(2a-x) = f(x)

If f(2a-x) = -f(x)

[sin(π-x)]4 [cos(π-x)]3 dx

= -sin4x cos3x dx

f(π-x) = -f(x)

So, the answer is 0.

Problem 2 :

Solution :

Let f(x) = log (1+x)/(1+x2)

Applying x = tan θ then θ = tan-1x

dx = sec2θ dθ

1+x2 = 1+tan2 θ

If x = 0, θ = tan-1(0) ==>  0

If x = 1, θ = tan-1(1) ==>  π/4

Problem 3 :

Solution :

Multiplying by its conjugate, we get

= π[sec x - tan x + x]

By applying the limits, we get

π[sec(π//2)-tan(π/2)+(π/2) - (sec0-tan0+0)]

π[(π/2) - 1]

= (π2/2)-π

Problem 4 :

Solution :

By applying limit, we get

2I = 3π/8 - π/8

2I = 2π/8

I = π/8

Problem 5 :

Solution :

Dividing by 2 and integrating it, we get

π[x] 0 to π/2

π(π/2)

π2/2

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