UNITARY METHOD DIRECT VARIATION
About "Unitary Method Direct Variation"
Unitary Method Direct Variation :
In this section, we are going to see, how problems on direct variation can be solved using unitary method.
First let us come to know what is direct variation.
What happens when..................
Thus we can say, If an increase in one quantity produces a proportionate increase in another quantity, then the quantities are said to be in direct variation.
or
If a decrease in one quantity produces a proportionate decrease in another quantity, then the quantities are said to be in direct variation.
Change in both the quantities must be same.
That is,
Increase -------> Increase
or
Decrease -------> Decrease
Unitary Method Definition and Example :
Definition :
Unitary-method is all about finding value to a single unit.
Unitary-method can be used to calculate cost, measurements like liters and time.
Example :
If 30 pens cost $45,
then the cost of one pen is = 45 / 30 = $1.50
Unitary Method Direct Variation - Practice problems
Let us look at some practice problems on "Unitary method direct variation"
Problem 1 :
75 basketballs cost $1,143.75. Find the cost of 26 basketballs
Solution :
This is a situation of direct variation.
Because,
less number of basket balls -----> cost will be less
Given : 75 basketballs cost $1,143.75
Cost of one basket ball is
= 1143.75 / 75
= $15.25
Then, the cost of 26 basket balls is
= 26 ⋅ 15.25
= 396.50
Hence, the cost of 26 basket balls is $ 396.50
Problem 2 :
If David sells 2 gallons of juice for $4, how much money will he earn by selling 17 gallons of juice ?
Solution :
This is a situation of direct variation.
Because,
more gallons of juice -----> amount received will be more
Given : 2 gallons of juice cost $4
Cost of one gallon of juice is
= 4 / 2
= $2
Cost of 17 gallons of juice is
= 17 ⋅ 2
= $34
Hence, David will earn $34 by selling 17 gallons of juice.
Problem 3 :
The cost of a taxi is $40.50 for 15 miles. Find the cost for 20 miles.
Solution :
This is a situation of direct variation.
Because,
more miles -----> cost will be more
Given : Cost for 15 miles is $40.50
Cost for one mile is
= 40.50 / 15
= $2.70
Then, the cost for 20 miles is
= 20 ⋅ 2.70
= 54
Hence, the cost for 20 miles is $54.
Problem 4 :
In a business, if A can earn $7500 in 2.5 years, At the same rate, find his earning for 4 years.
Solution :
This is a situation of direct variation.
Because,
more time -----> more earning
Given : Earning for 2.5 years is $7500
Earning for 1 year is
= 7500 / 2.5
= $3000
Then, earning for 4 years is
= 4 ⋅ 3000
= $12000
Hence, the earning for 4 years is $12000
Problem 5 :
In 36.5 weeks, Miguel raised $2,372.50 for cancer research. How much money will he raise in 20 weeks ?
Solution :
This is a situation of direct variation.
Because,
less number of weeks ----> amount raised will be less
Given : Miguel raised $2,372.50 in 36.5 weeks
Amount raised in one week is
= 2372.5 / 36.5
= $65
Amount raised in 20 weeks is
= 65 ⋅ 20
= $1300
Hence, the money raised in 20 weeks is $1300
Problem 6 :
Shanel gets 2/5 of a dollar for 1/7 hour of work.How much money does she get for 3 hours ?
Solution :
This is a situation of direct variation.
Because,
more hours -----> more earning
Pay for 1/7 hour of work = $2/5
Pay for 1 hour of work is
= (2/5) / (1/7)
= (2/5) ⋅ (7/1)
= 14 / 5
= $2.8
Then, pay for 3 hours of work is
= 2.8 ⋅ 3
= 8.4
Hence, Shanel gets $8.4 for 3 hours of work
Problem 7 :
If 3/35 of a gallon of gasoline costs 1/5 of a dollar, find the price of 1 gallon of gasoline.
Solution :
This is a situation of direct variation.
Because,
more gasoline -----> more cost
Cost of 3/35 of a gallon = $1/5
Cost of 1 gallon is
= (1/5) / (3/35)
= (1/5) ⋅ (35/3)
= 7 / 3
= 2.3
Hence, the cost of 1 gallon of gasoline is $ 2.30
Problem 8 :
Declan would like to hire a call taxi for 300 miles trip. If the cost of the taxi is $2.25 per mile, what is the total cost for his trip ?
Solution :
This is a situation of direct variation.
Because,
more miles -----> more cost
Cost for one mile = $2.25
Cost of 300 miles is
= 2.25 ⋅ 300
= $675
Hence, the total cost for the trip is $675.
Problem 9 :
John ordered 330 units of a product for $495. Then he reduced his order to 270 units. How much money does John have to pay for 270 units ?
Solution :
This is a situation of direct variation.
Because,
less units -----> less cost
Cost of 330 units = $495
Cost of 1 unit is
= 495 / 330
= 1.5
Cost of 270 units is
= 1.5 ⋅ 270
= $405
Hence, John has to pay $405 for 270 units.
Problem 10 :
My David earns $416 in 8 hours. How much does earn in 2.8 hours ?
Solution :
This is a situation of direct variation.
Because,
less hours -----> less earning
Given : Earning in 8 hours = $ 416
Earning in 1 hour = $ 52
Earning in 2.8 hours = 52 ⋅ 2.8 = 145.6
Hence, Mr. David will earn $145.6 in 2.8 hours.
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WORD PROBLEMS
HCF and LCM word problems
Word problems on simple equations
Word problems on linear equations
Word problems on quadratic equations
Area and perimeter word problems
Word problems on direct variation and inverse variation
Word problems on comparing rates
Converting customary units word problems
Converting metric units word problems
Word problems on simple interest
Word problems on compound interest
Word problems on types of angles
Complementary and supplementary angles word problems
Markup and markdown word problems
Word problems on mixed fractrions
One step equation word problems
Linear inequalities word problems
Ratio and proportion word problems
Word problems on sets and venn diagrams
Pythagorean theorem word problems
Percent of a number word problems
Word problems on constant speed
Word problems on average speed
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Domain and range of rational functions with holes
Graphing rational functions with holes
Converting repeating decimals in to fractions
Decimal representation of rational numbers
Finding square root using long division
L.C.M method to solve time and work problems
Translating the word problems in to algebraic expressions
Remainder when 2 power 256 is divided by 17
Remainder when 17 power 23 is divided by 16
Sum of all three digit numbers divisible by 6
Sum of all three digit numbers divisible by 7
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Sum of all three four digit numbers formed using 1, 2, 5, 6
