TRIGONOMETRIC RATIOS WORKSHEET

1. In the right triangle shown below, find the six trigonometric ratios of the angle θ.

2. In the right triangle shown below, find the six trigonometric ratios of the angle θ.

3. In triangle ABC, right angled at B, 15sinA = 12. Find the other five trigonometric ratios of the angle A. Also find the six ratios of the angle C.

4. In the right triangle PQR shown below, find the value of sinθ and cosθ. Using them, find the value of tanθ and cotθ.

5. From the figure given below, find the value of sinθ and cosθ. Using them, find the value of tanθ and cotθ.

6. In the diagram below, find the values of sinB, secB, cotB, cosC, tanC and cscC.

7. If sinθ = 13/85 and cosθ = 84/85, then find the values of tanθ and cosθ.

Answers

1. Answer :

From the triangle shown above,

opposite side = 5

adjacent side = 12

hypotenuse = 13

Therefore,

sinθ = PQ/RQ = 5/13

cosθ = PR/RQ = 12/13

tanθ = PQ/PR = 5/12

cscθ = RQPQ = 13/5

secθ = RQ/PR = 13/12

cotθ = PR/PQ = 12/5

2. Answer :

From the right triangle shown above,

AC = 24

BC = 7

By Pythagorean Theorem,

AB2 = BC2 + CA2

AB2 = 72 + 242

AB2 = 49 + 576

AB2 = 625

AB2 = 252

AB = 25 

Now, we can use the three sides to find the six trigonometric ratios of angle θ.

Therefore, 

sinθ = BC/AB = 7/25

cosθ = AC/AB = 24/25

tanθ = BC/AC = 7/24

cscθ = AB/BC = 25/7

secθ = AB/AC = 25/24

cotθ = AC/BC = 24/7

3. Answer :

Given : 15sinA = 12.

Therefore,

opposite side = 12

hypotenuse = 15

Let us consider the right triangle ABC where right angled at B, with    

BC = 12

AC = 15

By Pythagorean theorem,

AC2 = AB2 + BC2

152 = AB2 + 122

225 = AB2 + 144

225 - 144 = AB2

81 = AB2

9= AB2

9 = AB 

Now, we can use the three sides to find the five trigonometric ratios of angle A and six trigonometric ratios of angle C.

Therefore,

cosA = AB/AC = 9/15 = 3/5

tanA = BC/AB = 12/9 = 4/3

cscA = AC/BC = 15/12 = 5/4

secA = AC/AB = 15/9 = 5/3

cotA = AB/BC = 9/12 = 3/4

sinC = AB/AC = 9/15 = 3/5

cosC = BC/AC = 12/15 = 4/5

tanC = AB/BC = 9/12 = 3/4

cscC = AC/AB = 15/9 = 5/3

secC = AC/BC = 15/12 = 5/4

cotC = BC/AB = 12/9 = 4/3

4. Answer :

From the right triangle shown above,

opposite side = 5

adjacent side = 12

hypotenuse = 13

Therefore,

sinθ = PQ/RQ = 5/13

cosθ = PR/RQ = 12/13

tanθ = sinθ/cosθ = 5/13 ÷ 12/13

tanθ = 5/13 ⋅ 13/12

tanθ = 5/12

cotθ = cosθ/sinθ = 12/13 ÷ 5/13

cotθ = 12/13 ⋅ 13/5

cotθ = 12/5

5. Answer :

From the figure given above, AC = 24 and BC = 7.

By Pythagorean theorem,

AB2 = BC2 + CA2

AB2 = 72 + 242

AB2 = 49 + 576

AB2 = 49 + 576

AB= 625

AB2 = 252

AB = 25 

Now, we can use the three sides to find the six trigonometric ratios of angle θ.

Therefore,

opposite side = 7

adjacent side = 24

hypotenuse = 25

Therefore,

sinθ = BC/AB = 7/25

cosθ = AC/AB = 24/25

tanθ = sinθ/cosθ = 7/25 ÷ 24/25

tanθ = 7/25  25/24

tanθ = 7/24

sinθ = BC/AB = 7/25

cosθ = AC/AB = 24/25

cotθ = cosθ/sinθ = 24/25 ÷ 7/25

cotθ = 24/25 ⋅ 25/7

cotθ = 24/7

6. Answer :

In the right ΔABD, by Pythagorean Theorem,

AB2 = AD2 + BD2

132 = AD2 + 52

169 = AD2 + 25

Subtract 25 from each side.

144 = AD2

122 = AD2

12 = AD

In the right ΔACD, by Pythagorean Theorem,

AC2 = AD2 + CD2

AC2 = 122 + 162

AC2 = 144 + 256

AC2 = 400

AC2 = 202

AC = 20

Then,

sinB = opposite side/hypotenuse = AD/AB = 12/13

secB = hypotenuse/adjacent side = AB/BD = 13/5

cotB = adjacent side/opposite side = BD/AD = 5/12

cosC =  adjacent side/hypotenuse 

= CD/AC

= 16/20

= 4/5

tanC = opposite side/adjacent side

= AD/CD

= 12/16

= 3/4

cscC = hypotenuse/opposite side

= AC/AD

= 20/12

= 5/3

7. Answer :

Value of tanθ :

tanθ = sinθ/cosθ

= (13/85)/(84/85)

= (13/85)  (85/84)

= (13 ⋅ 85)/(85 ⋅ 84)

= 13/84

Value of cotθ :

cotθ = 84/13

Kindly mail your feedback to v4formath@gmail.com

We always appreciate your feedback.

©All rights reserved. onlinemath4all.com

Recent Articles

  1. Definition of nth Root

    Sep 29, 22 04:11 AM

    Definition of nth Root - Concept - Examples

    Read More

  2. Worksheet on nth Roots

    Sep 29, 22 04:08 AM

    Worksheet on nth Roots

    Read More

  3. Inverse Property of Multiplication Worksheet

    Sep 29, 22 12:02 AM

    Inverse Property of Multiplication Worksheet

    Read More