THE MEAN VALUE THEOREM FOR INTEGRALS

Example 1 :

Find the average value of the function f(x) = 2x + 6 over the interval [0, 7] and find c such that f(c) equals the average value of the function over [0, 7].

Solution :

Average value of the function :

Set the average value equal to f(c) and solve for c.

f(c) = 13

2c + 6 = 13

2c = 7

c = 3.5

Example 2 :

Find the average value of the function f(x) = ˣ⁄₂ over the interval [0, 6] and find c such that f(c) equals the average value of the function over [0, 6].

Solution :

Average value of the function :

Set the average value equal to f(c) and solve for c.

f(c) = 1.5

ᶜ⁄₂ = 1.5

c = 3

Example 3 :

Find the average value of the function f(x) = x² over the interval [0, 3] and find c such that f(c) equals the average value of the function over [0, 3].

Solution :

Average value of the function :

Set the average value equal to f(c) and solve for c.

f(c) = 3

c² = 3

c = ±√3

c ≈ -1.732 or 1.732

-1.732 ∉ [0, 3]  and  1.732 ∈ [0, 3]

Thus,

c ≈ 1.732

Example 4 :

Find the value of x, where the function f(x) = 2x + 3 attains its average value over the interval [0, 5].

Solution :

Let c be the value of x, where the function f(x) attains its average value over the interval [0, 5].

2c + 3 = 8

2c = 5

c = 2.5 ∈ [0, 5]

The given function attains its average value at x = 2.5 over the interval [0, 5].

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