Problem 1 :
The volume of the cube is 125 dm3. Find its side.
Solution :
Volume of cube = 125 dm3
a3 = 125
a3 = 53
a = 5 dm
So, the side length of cube is 5 dm.
Problem 2 :
A container is in the shape of a cube of side 20 cm. How much sugar can it hold?
Solution :
In order to find the quantity of sugar that the container can hold, we have to find the volume of container.
Side length of cubical container = 20 cm
Volume of container = a3
= (20)3
= 8000 cm3
Problem 3 :
A cubical tank can hold 64,000 liters of water. Find the length of the side of the tank.
Solution :
Let a be the side of the cubical tank. Volume of the tank is 27,000 litres. So,
V = a3 = (27000/1000)
a3 = 27
a = ∛27
a = 3 m
Problem 4 :
Three metallic cubes of side 3 cm, 4 cm and 5 cm respectively are melted and are recast into a single cube. Find the total surface area of the new cube.
Solution :
Side length of 1st cube = 3 cm
Side length of 2nd cube = 4 cm
Side length of 3rd cube = 5 cm
Volume of 1st, 2nd and 3rd cube = 33 + 43 + 53
= 27 + 64 + 125
= 216
a3 = 216
a3 = 63
a = 6 cm
Total surface area of new cube = 6a2
= 6(6)2
= 6(36)
= 216 cm2
So, total surface area of new cube 216 cm2
Problem 5 :
Find the L.S.A, T.S.A and volume of a cube of side 5 cm.
Solution :
Lateral surface area (L.S.A) = 4a2
= 4(52 ) = 100 sq. cm
Total surface area (T.S.A) = 6a2
= 6 (52 )
= 150 sq. cm
Volume of cube = a3
= 53
= 125 cm3
Problem 6 :
Find the length of the side of a cube whose total surface area is 216 square cm.
Solution :
Let a be the side of the cube.
Given that T.S.A = 216 sq. cm
6a2 = 216
a2 = 216/6
a2 = 36
a = √36
a = 6 cm
Problem 7 :
A cube has a total surface area of 384 sq. cm. Find its volume.
Solution :
Let a be the side of the cube. Given that T.S.A = 384 sq. cm
6a2 = 384
a2 = 384/6
a2 = 64
a = √64 = 8 cm
Hence, volume = a3 = 83 = 512 cm3
Problem 8 :
If the lateral surface area of a cube is 900 cm2, find the length of its side.
Solution :
Lateral surface area of cube = 4a2
4a2 = 900
a2 = 900/4
a2 = 225
a = √225
a = 15 cm
Hence the side of cube is 15 cm.
Problem 9 :
A cube has an edge length of 4 inches. You double the edge lengths. How many times greater is the volume of the new cube?
Solution :
Side length of cube = 4 inches
Doubling the side length, the new side length will be = 8 inches
Volume of old cube = 43
= 64 cubic inches
Volume of new cube = 83
= 512 cubic inches
Number of times = 512/64
= 8 times
So, volume of new cube is 8 times greater than volume of old cube.
Problem 10 :
Find the surface area of a cube with edge lengths of 9 centimeters.
Solution :
Side length of cube = 9 cm
Surface area = 6a2
= 6(9)2
= 6(81)
= 486 cm2
So, the total surface area of the cube is 486 cm2
Problem 11 :
How many 3/4 -centimeter cubes do you need to create a cube with an edge length of 12 centimeters?
Solution :
Volume of cube whose side length of 12 cm
= 123
= 1728 cm3
Volume of cube which has the side length of 3/4 cm
= (3/4)3
= 27/64 cm3
Number of cubes needed = 1728 / (27/64)
= 1728 x (64/27)
= 4096
Problem 12 :
A keychain-sized puzzle cube is made up of small cubes. Each small cube has a surface area of 1.5 square inches.
a. What is the side length of each small cube?
b. What is the surface area of the entire puzzle cube?

Solution :
a)
Surface area of cube = 1.5 square inches
6a2 = 1.5
a2 = 1.5/6
a2 = 0.25
a = 0.5 cm
b)
Side length of small cube = 3(1.5) ==> 4.5 cm
Surface area of cube (or) keychain = 6a2
= 6(4.5)2
= 6(20.25)
= 121.5 square inches
Problem 13 :
To finish a project, you need to paint the lateral surfaces of a cube with side length 2.5 inches. Find the area that you need to paint.
Solution :
Side length = 2.5 inches
Lateral surface area of cube = 4a2
= 4(2.5)2
= 4(6.25)
= 25 square inches
Kindly mail your feedback to v4formath@gmail.com
We always appreciate your feedback.
©All rights reserved. onlinemath4all.com
Nov 15, 25 08:00 AM
Nov 10, 25 06:30 PM
Nov 09, 25 07:02 PM