SURFACE AREA AND VOLUME OF A CUBE WORKSHEET

Problem 1 :

The volume of the cube is 125 dm3. Find its side.

Solution :

Volume of cube  =  125 dm3

a3  =  125

a3  =  53

a  =  5 dm

So, the side length of cube is 5 dm.

Problem 2 :

A container is in the shape of a cube of side 20 cm. How much sugar can it hold?

Solution :

In order to find the quantity of sugar that the container can hold, we have to find the volume of container.

Side length of cubical container  =  20 cm

Volume of container  =  a3

  =  (20)3

  =  8000 cm3

Problem 3 :

A cubical tank can hold 64,000 liters of water. Find the length of the side of the tank.

Solution :

Let a be the side of the cubical tank. Volume of the tank is 27,000 litres. So,

V  =  a3  =  (27000/1000)

a3  =  27

a  =  ∛27

a  =  3 m

Problem 4 :

Three metallic cubes of side 3 cm, 4 cm and 5 cm respectively are melted and are recast into a single cube. Find the total surface area of the new cube.

Solution :

Side length of 1st cube  =  3 cm

Side length of 2nd cube  =  4 cm

Side length of 3rd cube  =  5 cm

Volume of 1st, 2nd and 3rd cube  =  33 + 43 + 53

  =  27 + 64 + 125

  =  216

a3  =  216

a3  =  63

a  =  6 cm

Total surface area of new cube  =  6a2

  =  6(6)2

  =  6(36)

  =  216 cm2

So, total surface area of new cube 216 cm2

Problem 5 :

Find the L.S.A, T.S.A and volume of a cube of side 5 cm.

Solution :

Lateral surface area (L.S.A)  =  4a2

  =  4(52 ) = 100 sq. cm

Total surface area (T.S.A)  = 6a2

=  6 (52 )

=  150 sq. cm

Volume of cube  =  a3

  =  53

  =  125 cm3

Problem 6 :

Find the length of the side of a cube whose total surface area is 216 square cm.

Solution :

Let a be the side of the cube.

Given that T.S.A = 216 sq. cm

6a2  =  216 

a2  =  216/6 

a2  =  36

a  =  √36

a  =  6 cm

Problem 7 :

A cube has a total surface area of 384 sq. cm. Find its volume.

Solution :

Let a be the side of the cube. Given that T.S.A = 384 sq. cm

6a2 = 384

a2  =  384/6

a2  =  64

a  =  64  =  8 cm

Hence, volume = a3 = 83 = 512 cm3

Problem 8 :

If the lateral surface area of a cube is 900 cm2, find the length of its side.

Solution :

Lateral surface area of cube  =  4a2

4a2  =  900

a2  =  900/4

a2  =  225

a  =  √225

a  =  15 cm

Hence the side of cube is 15 cm. 

Problem 9 :

A cube has an edge length of 4 inches. You double the edge lengths. How many times greater is the volume of the new cube?

Solution :

Side length of cube = 4 inches

Doubling the side length, the new side length will be = 8 inches

Volume of old cube = 43

= 64 cubic inches

Volume of new cube = 83

= 512 cubic inches

Number of times = 512/64

= 8 times

So, volume of new cube is 8 times greater than volume of old cube.

Problem 10 :

Find the surface area of a cube with edge lengths of 9 centimeters.

Solution :

Side length of cube = 9 cm

Surface area = 6a2

= 6(9)2

= 6(81)

= 486 cm2

So, the total surface area of the cube is 486 cm2

Problem 11 :

How many 3/4 -centimeter cubes do you need to create a cube with an edge length of 12 centimeters?

Solution :

Volume of cube whose side length of 12 cm

= 123

= 1728 cm3

Volume of cube which has the side length of 3/4 cm 

= (3/4)3

= 27/64 cm3

Number of cubes needed = 1728 / (27/64)

= 1728 x (64/27)

= 4096 

Problem 12 :

A keychain-sized puzzle cube is made up of small cubes. Each small cube has a surface area of 1.5 square inches.

a. What is the side length of each small cube?

b. What is the surface area of the entire puzzle cube?

word-problems-on-surface-area-and-vol-cube-q1

Solution :

a)

Surface area of cube = 1.5 square inches

6a2 = 1.5

a2 = 1.5/6

a2 = 0.25

a = 0.5 cm

b)

Side length of small cube = 3(1.5) ==> 4.5 cm

Surface area of cube (or) keychain = 6a2

= 6(4.5)2

= 6(20.25)

= 121.5 square inches

Problem 13 :

To finish a project, you need to paint the lateral surfaces of a cube with side length 2.5 inches. Find the area that you need to paint.

Solution :

Side length = 2.5 inches

Lateral surface area of cube = 4a2

= 4(2.5)2

= 4(6.25)

= 25 square inches

Kindly mail your feedback to v4formath@gmail.com

We always appreciate your feedback.

©All rights reserved. onlinemath4all.com

Recent Articles

  1. 10 Hard SAT Math Questions (Part - 34)

    Nov 15, 25 08:00 AM

    digitalsatmath406.png
    10 Hard SAT Math Questions (Part - 34)

    Read More

  2. Algebra Word Problems Worksheet with Answers

    Nov 10, 25 06:30 PM

    tutoring.png
    Algebra Word Problems Worksheet with Answers

    Read More

  3. Tricky SAT Math Problems Solved Easily

    Nov 09, 25 07:02 PM

    digitalsatmath404.png
    Tricky SAT Math Problems Solved Easily

    Read More