SPECIAL RIGHT TRIANGLES WORKSHEET

Special Right Triangles Worksheet :

Worksheet given in this section will be much useful for the students who would like to practice problems on special right triangles.

Before look at the worksheet, if you would like to learn about special right triangles,

Special Right Triangles Worksheet - Problems

Problem 1 :

Find the length of the hypotenuse in the triangle shown below. Problem 2 :

Find the value of x in the triangle shown below. Problem 3 :

Find the value of s and x in the triangle shown below. Problem 4 :

A tipping platform is a ramp used to unload trucks, as shown in the picture below. How high is the end of an 70 foot ramp when it is tipped by a 30° angle ? by a 45° angle ? Problem 5 :

The road sign is shaped like an equilateral triangle. If the length of each side is  36 inches, estimate the area of the sign by finding the area of the equilateral triangle.  Special Right Triangles Worksheet - Solutions

Problem 1 :

Find the length of the hypotenuse in the triangle shown below. Solution :

By the Triangle Sum Theorem, the measure of the third angle is 45°.

The triangle is a 45°-45°-90° right triangle, so the length x of the hypotenuse is √2 times the length of a leg.

By 45°-45°-90° Triangle Theorem, we have

Hypotenuse  =  √2 ⋅ leg

In any right angled triangle, the side which is opposite the right angle is hypotenuse. In the triangle shown above, x represents hypotenuse. Because, the side x represents is opposite the right angle.

Substitute.

x  =  √2 ⋅ 3

Simplify.

x  =  3√2

Hence, the length of the hypotenuse is 3√2.

Problem 2 :

Find the value of x in the triangle shown below. Solution :

Because the triangle is an isosceles right triangle, its base angles are congruent. The triangle is a 45°-45°-90°right triangle, so the length of the hypotenuse is √2 times the length of a leg.

By 45°-45°-90° Triangle Theorem, we have

Hypotenuse  =  √2 ⋅ leg

Substitute.

5  =  √2 ⋅ x

Divide each side by √2.

5 / √2  =  x

To rationalize denominator in 5/√2, multiply numerator and denominator  by √2.

(√2/√2) ⋅ (5/√2)  =  x

5√2 / 2  =  x

Hence, the value of x is 5√2/2.

Problem 3 :

Find the value of s and x in the triangle shown below. Solution :

Finding the value of s :

Because the triangle is a 30°-60°-90° triangle, the longer leg is √3 times the length s of the shorter length.

By 30°-60°-90° Triangle Theorem, we have

Longer leg  =  √3 ⋅ shorter leg

Substitute.

5  =  √3 ⋅ s

Divide each side by √3.

5 / √3  =  s

To rationalize denominator in 5/√3, multiply numerator and denominator  by √3.

(√3/√3) ⋅ (5/√3)  =  s

5√3 / 3  =  s

So, the value of s is 5√3/3.

Finding the value of x :

By 30°-60°-90° Triangle Theorem, the length x of the hypotenuse is twice the length s of the shorter leg.

So, we have

Hypotenuse  =  ⋅ shorter leg

Substitute.

x  =  ⋅ (5√3 / 3)

x  =  10√3 / 3

So, the value of x is 10√3/3.

Problem 4 :

A tipping platform is a ramp used to unload trucks, as shown in the picture below. How high is the end of an 70 foot ramp when it is tipped by a 30° angle ? by a 45° angle ? Solution :

Part I :

Let h be the height of the ramp.

When the angle of elevation is 30°, we get a 30°-60°-90° special right triangle.

The height h of the ramp is the length of the shorter leg of the 30°-60°-90° triangle. And also, the length of the hypotenuse is 70 feet.

By 30°-60°-90° Triangle Theorem, we have

Hypotenuse  =  2 ⋅ Shorter length

70  =  2 ⋅ h

Divide each side by 2.

35  =  h

Part II :

When the angle of elevation is 45°, we get a 45°-45°-90° special right triangle.

By 45°-45°-90° Triangle Theorem, we have

Hypotenuse  =  √2 ⋅ Leg

70  =  √2 ⋅ h

Divide each side by √2.

70 / √2  =  h

Use calculator to approximate.

49.5  ≈  h

When the angle of elevation is 30°, the ramp height is 35 feet. When the angle of elevation is 45°, the ramp height is about 49 feet 6 inches.

Problem 5 :

The road sign is shaped like an equilateral triangle. If the length of each side is  36 inches, estimate the area of the sign by finding the area of the equilateral triangle. Solution : First find the height h of the triangle by dividing it into two 30°-60°-90° triangles. The length of the longer leg of one of these triangles is h. The length of the shorter leg is 18 inches.

By 30°-60°-90° Triangle Theorem, we have

h  =  √3 ⋅ 18

h  =  18√3

Use  h = 18√3 to find the area of the equilateral triangle.

Area  =  1/2 ⋅ b ⋅ h

Substitute.

Area  =  1/2 ⋅ 36 ⋅ 18√3

Use calculator to approximate.

Area    561.18

Hence, the area of the sign is about 561.18 square inches. After having gone through the stuff given above, we hope that the students would have understood how to solve problems on special right triangles.

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