# SOLVING WORD PROBLEMS WITH CUBOID

## About "Solving Word Problems with Cuboid"

Solving Word Problems with Cuboid :

Here we are going to see some practice questions on solving word problems with the shape cuboid.

If the length, breadth and height of a cuboid are l, b and h respectively.

Then

(i) Total Surface Area = 2 (lb + bh + lh ) sq.units.

(ii) Lateral Surface Area = 2 (l+b)h sq.units

(iii)  Volume  =  l b h

## Solving Word Problems with Cuboid - Practice questions

Question 1 :

Find the Total Surface Area and the Lateral Surface Area of a cuboid whose dimensions are: length = 20 cm, breadth = 15 cm and height = 8 cm

Solution :

Total surface area  =  2 (l b + b h + h l) sq.units

=  2[20(15) + 15(8) + 8(20)]

=  2 [300 + 120 + 160]

=  2(580)

=  1160 cm2

Lateral surface area  =  2 (l + b)h sq.units

=  2(20 + 15) 8

=  16 (35)

=  1260 cm2

Question 2 :

The dimensions of a cuboidal box are 6 m × 400 cm × 1.5 m. Find the cost of painting its entire outer surface at the rate of ₹22 per m2

Solution :

Length of cuboid  =  6 m

Breadth  =  400 cm  =  400/100  =  4 m

Height  =  1.5 m

Outer surface area has six sides.

=  2(lb + bh + hl)

=  2[6(4) + 4(1.5) + 1.5(6)]

=  2[24 + 6 + 9]

=  2

=  78

Cost of painting the surface  =  ₹22 per m2

Required cost  =  78(22)

=  1716

Question 3 :

The dimensions of a hall is 10 m × 9 m × 8 m. Find the cost of white washing the walls and ceiling at the rate of ₹8.50 per m2.

Solution :

Area of white washing = 2h(l + b) + lb

length  =  10 m, breadth  =  9 m and height  =  8  m

=  2 (8) (10 + 9) + 10  (9)

=  16 (19) + 90

=  304 + 90

=  394 m2

Cost of white washing  =  ₹8.50 per m2

Required cost  =  8.50(394)

=  ₹ 3349 After having gone through the stuff given above, we hope that the students would have understood, "Solving Word Problems with Cuboid"

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