SOLVING WORD PROBLEMS USING LINEAR EQUATIONS

About "Solving word problems using linear equations"

Solving word problems using linear equations :

We can write a linear equation for the information found in the given real-world problem and solve the problem using the linear equation.

In most of the cases, we use slope-intercept form equation to solve the real-world problems.

Solving word problems using linear equations - Examples

Example 1 :

The table shows the temperature of a fish tank during an experiment. Write the appropriate linear equation for the given situation and use the equation to find temperature at the 7th hour. . Solution :

Step 1 :

Notice that the change in the temperature is the same for each increase of 1 hour in time. So, the relationship is linear.

Since we want to find the temperature at the 7th hour, the appropriate linear equation for the given situation is slope-intercept form (y = mx + b), assuming "y" as temperature and "x" as hours.

Step 2 :

Choose any two points in the form (x, y), from the table to find the slope :

For example, let us choose (0, 82) and (1, 80).

Use the slope formula.

m  =  (y₂ - y₁) / (x₂ - x₁)

Substitute (0, 82) for (x₁, y) and (1, 80) for (x, y₂).

m  =  (80 - 82) / (1 - 0)

m  =  -2 / 1

m  =  -2

Step 3 :

Find the y-intercept using the slope and any point from the table.

Slope-intercept form equation of a line :

y  =  mx + b

Plug m  =  -2, and (x, y)  =  (0, 82)

82  =  -2(0) + b

82  =  0 + b

82  =  b

Step 4 :

Now, plug m = -2 and b = 82 in slope-intercept form equation of a line.

y  =  mx + b

y  =  -2x + 82

Step 5 :

Find the temperature at the 7th hour.

Plug x = 7 in the equation y = -2x + 82.

y  =  -2(7) + 82

y  =  -14 + 82

y  =  68

Hence, the temperature at the 7th hour is 68⁰ F.

Let us look at the next example on "Solving word problems using linear equations"

Example 2 :

Lily has just opened her new computer store. She makes \$25 on every computer she sells and her monthly expenses are \$10,000. What is the minimum number of computer does she need to sell in a month to make a profit ?

Solution :

Step 1 :

Let "y" stand for the profit and "x' stand for number of computers sold.

From the given information, we have

Profit  =  27 x No. of computers sold - Monthly expenses

y  =  27x -10,000

Step 2 :

Let us find the number of computers sold for no profit.

That is, find the value of "x" when y = 0.

Plug y = 0 in the equation y = 27x - 10,000.

0  =  25x - 10,000

10,000  =  25x

Divide both sides by 25.

10,000 / 25  =  25x / 25

400  =  x

Step 3 :

When Lily sells 400 computers in a month, her profit is equal to zero.

So, she has to sell more than 400 computer per month to make a profit.

To make a profit, the minimum number of computers per month, she needs to sell is 401.

Let us look at the next example on "Solving word problems using linear equations"

Example 3 :

Elizabeth’s cell phone plan lets her choose how many minutes are included each month. The table shows the plan’s monthly cost y for a given number of included minutes x. Write an equation in slope-intercept form to represent the situation and use it to estimate cost of plan for 800 minutes included. Solution :

Step 1 :

Notice that the change in cost is the same for each increase of 100 minutes. So, the relationship is linear.

Step 2 :

Choose any two points in the form (x, y), from the table to find the slope :

For example, let us choose (100, 14) and (200, 20).

Use the slope formula.

m  =  (y₂ - y₁) / (x₂ - x₁)

Substitute (100, 14) for (x₁, y) and (200, 20) for (x, y₂).

m  =  (20 - 14) / (200 - 100)

m  =  6 / 100

m  =  0.06

Step 3 :

Find the y-intercept using the slope and any point from the table.

Slope-intercept form equation of a line :

y  =  mx + b

Plug m  =  0.06, and (x, y)  =  (100, 14)

14  =  0.06(100) + b

14  =  6 + b

8  =  b

Step 4 :

Now, plug m = 0.06 and b = 8 in slope-intercept form equation of a line.

y  =  mx + b

y  =  0.06x + 8

Step 5 :

Estimate cost of plan for 800 minutes included.

Plug x = 800 in the equation y = 0.06x + 8.

y  =  0.06(800) + 8

y  =  48 + 8

y  =  56

Hence, the cost of plan for 800 minutes included is \$56.

Let us look at the next example on "Solving word problems using linear equations"

Example 4 :

The rent charged for space in an office building is a linear relationship related to the size of the space rented.At west main street office rentals, \$750 rent charged for 600 square feet of space and \$1150 rent charged for 900 square feet of space. Write an equation in slope-intercept form for the rent at West Main Street Office Rentals and use it to calculate the rent for 1200 square feet of space.

Solution :

Step 1 :

Identify the independent and dependent variables.

The independent variable (x) is the square footage of floor space.

The dependent variable (y) is the monthly rent.

Step 2 :

Write the information given in the problem as ordered pairs.

The rent for 600 square feet of floor space is \$750 :

(600, 750)

The rent for 900 square feet of floor space is \$1150 :

(900, 1150)

Step 3 :

Find the slope.

m  =  (y₂ - y) / (x - x)

Substitute (600, 750) for (x, yand (900, 1150) for (x, y).

m  =  (1150 - 750) / (900 - 600)

m  =  400 / 300

m  =  4/3

Step 4 :

Find the y-intercept.

Use the slope 4/3 and one of the ordered pairs (600, 750).

Slope-intercept form :

y  =  mx + b

Plug m = 4/3,  x = 600 and y = 750.

750  =  (4/3)(600) + b

750  =  (4)(200) + b

750  =  800 + b

-50  =  b

Step 5 :

Substitute the slope and y-intercept.

Slope-intercept form

y  =  mx + b

Plug m = 4/3 and b = -50

y  =  (4/3)x + (-50)

y  =  (4/3)x - 50

Step 6 :

Calculate the rent for 1200 square feet of space.

Plug  x = 1200 in the equation y = (4/3)x - 50.

y  =  (4/3)(1200) - 50

y  =  1600 - 50

y  =  1550

Hence, the rent for 1200 square feet of space is \$1550. After having gone through the stuff given above, we hope that the students would have understood "Solving word problems using linear equations".

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