# SOLVING WORD PROBLEMS USING ARITHMETIC PROGRESSION

Solving Word Problems Using Arithmetic Progression :

The examples given in this section will be useful to understand,  how we solve word problems with the concept arithmetic progression.

## Solving Word Problems Using Arithmetic Progression - Examples

Question 1 :

Subba Rao started work in 1995 at an annual salary of \$ 5000 and received and increment of 200 each year. In which year did his income reach \$ 7000

Solution :

5000, 5200,,...........7000

a = 5000, d = 5200 - 5000  =  200, an = 7000

an = a + (n - 1) d

7000  =  5000 + (n - 1) 200

7000 - 5000  =  (n - 1) 200

2000  =  (n - 1) 200

n - 1  =  2000/200

n - 1  =  10

n  =  10 + 1

n  =  11

Hence 11th year his salary will be 7000.

Question 2 :

John saved \$5 in the first week of a year and then increased her weekly savings by \$1.75. If the nth week, her weekly savings become \$20.75, find n.

Solution :

a = 5  d = 1.75  an = 20.75

an = a + (n - 1) d

20.75 = 5 + (n - 1) 1.75

20.75 - 5 = (n - 1) 1.75

15.75 = ( n - 1) 1.75

15.75/1.75 = n - 1

9 = n - 1

n - 1 = 9

n = 9 + 1

n = 10

After having gone through the stuff given above, we hope that the students would have understood the concept of solving word problems using arithmetic progression.

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