# SOLVING SYSTEMS OF EQUATIONS WORD PROBLEMS BY ELIMINATION METHOD

Solving Systems of Equations Word Problems by Elimination Method :

In this section, you will learn how to solve system of equations word problems using elimination method.

## Solving Systems of Equations Word Problems by Elimination Method - Examples

Example 1 :

The sum of two numbers is 7. The difference between 5 times the larger and 3 times the smaller is equal 11. Find the numbers.

Solution :

Let 'x' and 'y' be the two numbers such that x > y.

Given : The sum of two numbers is 7.

Then,

x + y  =  7 -----(1)

Given : The difference between 5 times the larger and 3 times the smaller is equal 11.

Then,

5x - 3y  =  11 -----(2)

Solve (1) and (2) using elimination :

Eliminate one of the variables to get the value of the other variable.

In (1) and (2), both the variables 'x' and 'y' do not have the same coefficient.

One of the variables must have the same coefficient.

So, multiply both sides of (1) by 3 to make the coefficients of 'y' same.

(1) ⋅ 3 ----->  3x + 3y  =  21 -----(3)

In (2) and (3), 'y' has the same coefficient with different signs.

Add (2) and (3) to eliminate the variable 'y' and solve for 'x'.

(2) + (3) :

8x  =  32

Divide each side by 8.

x  =  4

Substitute 4 for x in (1).

(1)-----> 4 + y  =  7

Subtract 4 from each side.

y  =  3

Therefore, the two numbers are 3 and 4.

Example 2 :

The monthly incomes of A and B are in the ratio 3:4 and their monthly expenditures are in the ratio 5:7. If each saves ₹ 5,000 per month, find the monthly income of each.

Solution :

Given : The monthly incomes of A and B are in the ratio 3 : 4.

Then, the monthly incomes of A and B can be assumed as 3x and 4x respectively.

Given : The monthly expenditures of A and B are in the ratio 5 : 7.

Then, the monthly expenditures of A and B can be assumed as 5y and 7y respectively.

The relationship between income, expenditure and savings is

Income - Expenditure  =  Savings

Then,

3x - 5y  =  5000  ------(1)

4x - 7y  =  5000  ------(2)

Because we have to find the monthly incomes of A and B, we need the value of x.

So, we have to eliminate 'y' in the above two equations.

In (1) and (2), 'y' does not have the same coefficient.

So, multiply both sides of (1) by 7 and (2) by -5 to make the coefficients of 'y' same with different signs in the equations.

(1) ⋅ 7  :

21x - 35y  =  35000 ------(3)

(1) ⋅ -5  :

-20x + 35y  =  -25000 ------(4)

Add (3) and (4) to eliminate 'y' and find the value of 'x'.

x  =  10000

Monthly income of A  =  3x  =  3(10000)  =  30000

Monthly income of B  =  4x  =  4(10000)  =  40000

After having gone through the stuff given above, we hope that the students would have understood how to solve systems of equations word problems using elimination method.

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