SOLVING PERCENT EQUATIONS WORKSHEET

Problem 1 : 

Solve for x : 

20% of x is 16

Problem 2 : 

Solve for x : 

x% of 18x is 0.9

Problem 3 : 

Solve for x : 

15% of 50 is x

Problem 4 : 

If 5 more than 10 percent of x is 85, then  find the value of x. 

Problem 5 : 

If 10 less than 8 percent of x is 26, then  find the value of x. 

Problem 6 : 

Sum of x and y is 150. Sum of 5 percent of x and 10 percent of y is 11. Find the values of x and y 

Detailed Answer Key

Problem 1 : 

Solve for x : 

20% of x is 16

Solution : 

20% of x is 16

0.2x  =  16

Divide each side by 0.2

x  =  80

Problem 2 : 

Solve for x : 

x% of 18x is 0.9

Solution : 

x% of 18 is 0.9

0.01x ⋅ 18  =  0.9

0.18x  =  0.9

Divide each side by 0.18

x  =  5

Problem 3 : 

Solve for x : 

15% of 50 is x

Solution : 

15% of 50 is x

0.15 ⋅ 50  =  x

7.5  =  x

Problem 4 : 

If 5 more than 10 percent of x is 85, then  find the value of x. 

Solution : 

5 more than 10 percent of x is 85

10% of x + 5  =  85

0.1x + 5  =  85

Subtract 5 from each side. 

0.1x  =  80

Divide each side by 0.1

x  =  800

Problem 5 : 

If 10 less than 8 percent of x is 26, then  find the value of x. 

Solution : 

10 less than 8 percent of x is 26

8% of x - 10  =  26

0.08x - 10  =  26

Add 10 to each side. 

0.08x  =  36

Divide each side by 0.08

x  =  450

Problem 6 : 

Sum of x and y is 150. Sum of 5 percent of x and 10 percent of y is 11. Find the values of x and y 

Solution : 

Given : Sum of x and y is 150.

Then, we have 

x + y  =  150

Subtract y from each side. 

x  =  150 - y -----(1)

Given : Sum of 5 percent of x and 10 percent of y is 11.

Then, we have 

5% of x + 10% of y  =  11

0.05x + 0.1y  =  11

To get rid of the decimals, multiply each side by 100. 

5x + 10y  =  1100

Divide each side by 5.

x + 2y  =  220

From (1), substitute (150 - y) for x.

150 - y + 2y  =  220

150 + y  =  220

Subtract 150 from each side. 

y  =  70

Substitute 70 for y in (1). 

(1)-----> x  =  150 - 70

x  =  80

So, the values of x and y are 80 and 70 respectively.

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