# SOLVING MULTI STEP WORD PROBLEMS

In this section, you will learn how to solve multi step word problems.

## Solving Multi Step Word Problems - Examples

Example 1 :

The denominator of a fraction exceeds the numerator by 5. If 3 be added to both, the fraction becomes 3/4. Find the fraction.

Solution :

Step 1 :

Let 'x' be the numerator.

"The denominator of the fraction exceeds the numerator"

From the above information,

Fraction  =  x / (x + 5) ------(1)

Step 2 :

"If 3 be added to both, the fraction becomes 3/4"

From the above information, we have

(x + 3) / (x + 5 + 3)  =  3/4

Step 3 :

Simplify the expression in step 2.

(x + 3)/(x + 8)  =  3/4

4(x + 3)  =  3(x + 8)

4x + 12  =  3x + 24

x  =  12

Step 4 :

Substitute 12 for x in (1).

x / (x + 5)  =  12 / (12 + 5)

x / (x + 5)  =  12/27

So, the required fraction is 12/27.

Example 2 :

If thrice of A's age 6 years ago be subtracted from twice his present age, the result would be equal to his present age. Find A's present age.

Solution :

Step 1 :

Let 'x' be A's present age.

A's age 6 years ago  =  x - 6

Step 2 :

Thrice of A's age 6 years ago  =  3(x-6) --------(1)

Step 3 :

Twice his present age  =  2x --------(2)

Step 4 :

According to the question,

(2) - (1)  =  A's present age

2x - 3(x-6)  =  x

2x - 3x + 18  =  x

- x + 18  =  x

18  =  2x

9  =  x

So, A's present age is 9 years.

Example 3 :

A number consists of two digits. The digit in the tens place is twice the digit in the units place. If 18 be subtracted from the number, the digits are reversed. Find the number.

Solution :

Step 1 :

Let "x" be the digit in units place.

Then the digit in the tens place = 2x

Step 2 :

According to the question,

(2x)x - 18  =  x(2x)

(2x)10 + (x)1 - 18  =  (x)10 + (2x)1

20x + x - 18  =  10x + 2x

21x - 18  =  12x

21x - 18  =  12x

9x  =  18

x  =  2

Step 3 :

So, the digit at the units place is

x  =  2

And the digit at the tens place is

=  2x

=  2(2)

=  4

So, the required number is 42.

Example 4 :

The width of the rectangle is 2/3 of its length. If the perimeter of the rectangle is 80 cm. Find its area.

Solution :

Step 1 :

Let 'x' be the length of the rectangle.

Then, width of the rectangle  =  (2/3)x

Step 2 :

Perimeter  =  80 cm

2(l + w)  =  80

l + w  =  40

x + (2/3)x  =  40

(3x + 2x) / 3  =  40

5x/3  =  4

5x  =  120

x  =  24

So, the length is 24 cm.

Step 3 :

Width  =  (2/3)x

Width  =  (2/3)24

Width  =  16 cm

Step 4 :

Area of the rectangle  =  l x w

Area of the rectangle  =  24 x 16

Area of the rectangle  =  384 square cm

Example 5 :

The ratio of the no. of boys to the no. of girls in a school of 720 students is 3:5. If 18 new girls are admitted in the school, find how many new boys may be admitted so that the ratio of the no. of boys to the no. of girls may change to 2:3.

Solution :

Step 1 :

Sum of the terms in the given ratio is

=  3 + 5

=  8

So, no. of boys in the school is

=  720 x (3/8)

=  270

No. of girls in the school is

=  720 x (5/8)

=  450

Step 2 :

Let 'x' be the no. of new boys admitted in the school.

No. of new girls admitted is 18  (given).

no. of boys in the school  =  270 + x

no. of girls in the school  =  450 + 18  =  468

Step 3 :

The ratio after the new admission is 2 : 3 (given).

So, we have

(270 + x) : 468  =  2 : 3

3(270 + x)  =  468 x 2

(using cross product rule in proportion)

810 + 3x  =  936

3x  =  126

x  =  42

So, the number of new boys admitted in the school is 42. Apart from the stuff given above, if you need any other stuff in math, please use our google custom search here.

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