**Solving Mensuration Word Problems with the Shape Cuboid :**

Here we are going to see some practice questions solving mensuration word problems with the shape cuboid.

If the length, breadth and height of a cuboid are l, b and h respectively.

Then

(i) Total Surface Area = 2 (lb + bh + lh ) sq.units.

(ii) Lateral Surface Area = 2 (l+b)h sq.units

(iii) Volume = l b h

**Question 1 :**

Find the volume of a cuboid whose dimensions are

(i) length = 12 cm, breadth = 8 cm, height = 6 cm

(ii) length = 60 m, breadth = 25 m, height = 1.5 m

**Solution :**

(i) length = 12 cm, breadth = 8 cm, height = 6 cm

Volume of cuboid = l b h

= 12 (8) (6)

= 12 (48)

= 576 cm^{3}

(ii) length = 60 m, breadth = 25 m, height = 1.5 m

Volume of cuboid = l b h

= 60 (25) (1.5)

= 60 (37.5)

= 2250 cm^{3}

**Question 2 :**

The dimensions of a match box are 6 cm × 3.5 cm × 2.5 cm. Find the volume of a packet containing 12 such match boxes.

**Solution :**

length = 6 cm, breadth = 3.5 cm and height = 2.5 cm

Volume of cuboid = lbh

= 6 (3.5) (2.5)

= 52.5 cm^{3}

Volume of 12 boxes = 52.5 (12)

= 630 cm^{3}

**Question 3 :**

The length, breadth and height of a chocolate box are in the ratio 5 : 4 : 3. If its volume is 7500 cm^{3}, then find its dimensions.

**Solution :**

Volume of box = 7500 cm^{3}

Let 5x, 4x and 3x be the length breadth and height of chocolate boxes respectively.

5x (4x) (3x) = 7500

60x^{3} = 7500

x^{3} = 125

x = 5 cm

length = 5(5) = 25 cm

breadth = 4(5) = 20 cm

height = 3(5) = 15 cm

After having gone through the stuff given above, we hope that the students would have understood, "Solving Word Problems with Cuboid"

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