In this page solving equations worksheet1 solution3 we are going to see solution of practice questions.

**Question 3:**

Solving equation (b - c) x² + (c - a) x + (a - b) = 0

**Solution:**

a = (b - c) b = (c - a) c = (a - b)

x = [- b ± √(b² - 4 a c)]/2 a

x = - (c - a) ± √((c - a)² - 4 (b - c) (a - b))]/[2 (b - c)]

x = - c + a ± √[c² + a² - 2 ac - 4 (ab - b² - ac + bc)]/[2 (b - c)]

x = - c + a ± √[c² + a² - 2 ac - 4ab + 4 b² + 4 ac - 4 bc)]/[2 (b - c)]

x = - c + a ± √[a² + 4 b² + c² + 2 ac - 4ab - 4 bc)]/[2 (b - c)]

x = - c + a ± √[a² + (-2b)² + c² + 2 a (-2b)+ 2 (-2b) c + 2 ca)]/[2 (b - c)]

x = [- c + a ± √(a -2b+c)²]/[2 (b - c)]

x = [- c + a ± (a -2b+c)]/[2 (b - c)]

x = [- c + a + (a -2b+c)]/[2 (b - c)] , x = [- c + a - (a -2b+c)]/[2 (b - c)]

x = [- c + a + a -2b+c]/[2 (b - c)] , x = [- c + a - a + 2b- c)]/[2 (b - c)]

x = [2a -2b]/[2 (b - c)] , x = [- 2c + 2b)]/[2 (b - c)]

x = 2(a -b)/[2 (b - c)] , x = 2(b - c)/[2 (b - c)]

x = (a -b)/(b - c) , x = 1

Therefore the correct answer is option A

**(A) [(a - b)/(b - c)] , 1**

(B) [(a - b) (b - c)] , 1

(C) [(b - c)/(a - b)] , 1

(D) None

solving equations worksheet1 solution3 solving equations worksheet1 solution3

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- Roots of Polynomial of Degree4
- Roots of Polynomial of Degree5
- Synthetic division
- Rational Expressions
- Rational Zeros Theorem
- LCM -Least Common Multiple
- GCF-Greatest Common Factor
- Simplifying Rational Expressions
- Factorize of Polynomials
- Factoring Worksheets
- Framing Quadratic Equation From Roots
- Framing Quadratic Equation Worksheet
- Remainder Theorem
- Relationship Between Coefficients and roots
- Roots of Cubic equation
- System Of Linear Equations