Solving Equations Worksheet1 Solution2





In this page solving equations worksheet1 solution2 we are going to see solution of practice questions.

Question 2:

The values of x in the equation 7 (x + 2p)² + 5 p² = 35 x p + 117 p²

Solution:

7 (x + 2p)² + 5 p² = 35 x p + 117 p²

7 [x² + (2p)² + 2 x (2p)] + 5 p² = 35 xp + 117 p²

7 [x² + 4p² + 4 x p] + 5 p² = 35 xp + 117 p²

7 x² + 28 p² + 28 x p - 35 xp - 117 p² + 5 p²  = 0

7 x² - 7 x p - 117 p² + 28 p²  + 5 p² = 0

7 x² - 7 x p - 84 p²  = 0

By simplifying the original equation we get this quadratic equation of variable x. For solving this equation let us factorize this quadratic equation.

7 x² - 7 x p - 84 p²  = 0

7 x² - 28 x p + 21 x p - 84 p²  = 0

7 x (x - 4p) + 21 p (x - 4 p) = 0

(7 x + 21 p) (x - 4 p) = 0

 (7 x + 21 p) = 0            (x - 4 p) = 0

       7 x = - 21 p                     x = 4 p

         x = -21p/7             

         x = -3 p

value of x are 4 p, -3 p

Therefore the correct answer is option (A)

(A)  (4 p , - 3 p)

(B)  (4 p ,  3 p)

(C)  (-4 p , 3 p)

(D)  (-4 p , - 3 p)

solving equations worksheet1 solution2 solving equations worksheet1 solution2