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Problems 1-11 : Solve for x.
Problem 1 :
Λ£βββ = β
Problem 2 :
Β²Λ£βββ = βΆββ
Problem 3 :
Λ£ββ = Λ£ββ - 1
Problem 4 :
β΅Λ£ββ - Λ£ββ = β»Β³ββ
Problem 5 :
Λ£ββ - Β³Λ£ββ = ΒΎ - x
Problem 6 :
β½Λ£ βΊ ΒΉβΎββ = β½Λ£ β» ΒΉβΎββ
Problem 7 :
Λ£ββ - β = Λ£ββ + ΒΌ
Problem 8 :
Λ£ββ - Β³Λ£ββ + β΅Λ£ββ = 21
Problem 9 :
x + 7 - βΈΛ£ββ = ΒΉβ·ββ - β΅Λ£ββ
Problem 10 :
β½Λ£ βΊ β΄βΎβββ - β½Λ£ β» β΅βΎβββ = 1
Problem 11 :
β½Β³Λ£ β» Β²βΎββ - β½Β²Λ£ βΊ Β³βΎββ = β - x
Problem 12 :
Subtracting two-third of a number from 5 results 3. Find the number.

1. Answer :
Λ£βββ = β
Least common multiple of the denominators 12 and 3 is 12.
Multiply both sides of the equation by 12 to get rid of the denominators 12 and 3.
12(Λ£βββ) = 12(β )
x = 4(2)
x = 8
2. Answer :
Β²Λ£βββ = βΆββ
Least common multiple of the denominators 15 and 5 is 15.
Multiply both sides of the equation by 15 to get rid of the denominators 15 and 5.
15(Β²Λ£βββ ) = 15(βΆββ )
2x = 3(6)
2x = 18
Divide both sides by 2.
x = 9
3. Answer :
Λ£ββ = Λ£ββ - 1
Least common multiple of the denominators 2 and 3 is 6.
Multiply both sides of the equation by 6 to get rid of the denominators 2 and 3.
6(Λ£ββ) = 6(Λ£ββ - 1)
3x = 6(Λ£ββ) - 6(1)
3x = 2x - 6
Subtract 2x from both sides.
x = -6
4. Answer :
β΅Λ£ββ - Λ£ββ = β»Β³ββ
Least common multiple of the denominators 4 and 2 is 4.
Multiply both sides of the equation by 4 to get rid of the denominators 4 and 2.
4(β΅Λ£ββ - Λ£ββ) = 4(β»Β³ββ)
4(β΅Λ£ββ) - 4(Λ£ββ) = -3
5x - 2x = -3
3x = -3
Divide both sides by 3.
x = -1
5. Answer :
Λ£ββ - Β³Λ£ββ = ΒΎ - x
Least common multiple of the denominators 2 and 4 is 4.
Multiply both sides of the equation by 4 to get rid of the denominators.
4(Λ£ββ - Β³Λ£ββ) = 4(ΒΎ - x)
4(Λ£ββ) - 4(Β³Λ£ββ) = 4(ΒΎ) - 4(x)
2x - 3x = 3 - 4x
-x = 3 - 4x
Add 4x to both sides.
3x = 3
Divide both sides by 3.
x = 1
6. Answer :
β½Λ£ βΊ ΒΉβΎββ = β½Λ£ β» ΒΉβΎββ
Least common multiple of the denominators 3 and 5 is 15.
Multiply both sides of the equation by 15 to get rid of the denominators 3 and 5.
15[β½Λ£ βΊ ΒΉβΎββ] = 15[β½Λ£ β» ΒΉβΎββ ]
5(x + 1) = 3(x - 1)
5x + 5 = 3x - 3
Subtract 3x from both sides.
2x + 5 = -3
Subtract 5 from both sides.
2x = -8
Divide both sides by 4.
x = -4
7. Answer :
Λ£ββ - β = Λ£ββ + ΒΌ
Least common multiple of the denominators 2, 5, 3 and 4 is 60.
Multiply each side of the above equation by 60 to get rid of the denominators.
60(Λ£ββ - β ) = 60(Λ£ββ + ΒΌ)
Using Distributive Property,
60(Λ£ββ) - 60(β ) = 60(Λ£ββ) + 60(ΒΌ)
30x - 12 = 20x + 15
Subtract 20x from both sides.
10x - 12 = 15
Add 12 to each side.
10x = 27
Divide each side by 10.
x = Β²β·βββ
8. Answer :
Λ£ββ - Β³Λ£ββ + β΅Λ£ββ = 21
Least common multiple of the denominators 2, 4 and 6 is 12.
Multiply each side of the above equation by 12 to get rid of the denominators.
12(Λ£ββ - Β³Λ£ββ + β΅Λ£ββ) = 12(21)
Using Distributive Property,
12(Λ£ββ) - 12(Β³Λ£ββ) + 12(β΅Λ£ββ) = 252
6x - 9x + 10x = 252
7x = 252
x = 36
9. Answer :
x + 7 - βΈΛ£ββ = ΒΉβ·ββ - β΅Λ£ββ
Least common multiple of the denominators 3, 6 and 2 is 6.
Multiply each side of the above equation by 6 to get rid of the denominators.
6(x + 7 - βΈΛ£ββ) = 6(ΒΉβ·ββ - β΅Λ£ββ)
Using Distributive Property,
6(x) + 6(7) - 6(βΈΛ£ββ) = 6(ΒΉβ·ββ) - 6(β΅Λ£ββ)
6x + 42 - 16x = 17 - 15x
-10x + 42 = 17 - 15x
Add 15x to each side.
5x + 42 = 17
Subtract 42 from each side.
5x = -25
Divide each side by 5.
x = -5
10. Answer :
β½Λ£ βΊ β΄βΎβββ - β½Λ£ β» β΅βΎβββ = 1
Least common multiple of the denominators 12 and 18 is 36.
Multiply each side of the above equation by 36 to get rid of the denominators.
36[β½Λ£ βΊ β΄βΎβββ - β½Λ£ β» β΅βΎβββ] = 36(1)
Using Distributive Property,
36[β½Λ£ βΊ β΄βΎβββ] - 36[β½Λ£ β» β΅βΎβββ] = 36
3(x + 4) - 2(x - 5) = 36
3x + 12 - 2x + 10 = 36
x + 22 = 36
Subtract 22 from each side.
x = 14
11. Answer :
β½Β³Λ£ β» Β²βΎββ - β½Β²Λ£ βΊ Β³βΎββ = β - x
Least common multiple of the denominators 4 and 3 is 12.
Multiply each side of the above equation by 12 to get rid of the denominators.
12[β½Β³Λ£ β» Β²βΎββ - β½Β²Λ£ βΊ Β³βΎββ] = 12(β - x)
Distribute.
12[β½Β³Λ£ β» Β²βΎββ] - 12[β½Β²Λ£ βΊ Β³βΎββ] = 12(β ) - 12(x)
3(3x - 2) - 4(2x + 3) = 4(2) - 12x
9x - 6 - 8x - 12 = 8 - 12x
x - 18 = 8 - 12x
Add 12x to each side.
13x - 18 = 8
Add 18 to each side.
13x = 26
Divide each side by 13.
x = 2
12. Answer :
Let x be the number.
It is given that subtracting two-third of a number from 5 results 3.
5 - (β )x = 3
5 - ο»ΏΒ²Λ£ββο»Ώ = 3
Multiply both sides by 3 to get rid of the denominator.
3(5 - ο»ΏΒ²Λ£ββ) = 3(3)
3(5) - 3(Β²Λ£ββ) = 9
15 - 2x = 9
Subtract 15 from both sides.
-2x = -6
Divide both sides by -2.
x = 3
The number is 3.
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