To solve equations with rational exponents, we have to isolate the variable for which we have rational exponent.
If we have power 3/2, to get rid of 2 which is at the denominator, we have to raise power 2 on both sides.
If we have power 5/3, to get rid of 3 which is at the denominator, we have to raise power 2 on both sides
Solve the rational exponent problems of x.
Example 1 :
4x1/3 = 20
Solution :
4x1/3 = 20
Divide by 4 on both sides.
x1/3 = 5
Raise power 3 on both sides.
(x1/3)3 = 53
x = 125
Example 2 :
3x1/4 = 15
Solution :
3x1/4 = 15
Divide by 3 on both sides.
x1/4 = 5
(x1/4)4 = 54
x = 625
Example 3 :
3x3/4 = 24
Solution :
3x3/4 = 24
Divide by 3 on both sides.
x3/4 = 8
Raise power 4 on both sides.
(x3/4)4 = 84
x3 = 84
x = ∛84
x = ∛(8⋅8⋅8⋅8)
x = 8∛8
x = 8∛(2⋅2⋅2)
x = 8(2)
x = 16
Example 4 :
4x1/3 + 20 = 0
Solution :
4x1/3 + 20 = 0
Subtract 20 on both sides.
4x1/3 = -20
Divide by 4 on both sides.
x1/3 = -5
Raise power 3 on both sides.
x = (-5)3
x = -125
Example 5 :
x4/3 - 16 = 0
Solution :
x4/3 - 16 = 0
Add 16 on both sides.
x4/3 = 16
Raise power 3 on both sides.
x4 = 163
x = ∜163
x = ∜(16⋅16⋅16)
x = ∜(4⋅4⋅4⋅4⋅4⋅4)
x = 4∜(2⋅2⋅2⋅2)
x = 4(2)
x = 8
Example 6 :
(x-3)3/2 = 27
Solution :
(x-3)3/2 = 27
Raise power on both sides.
(x-3)3 = 272
Take cube root on both sides.
∛(x-3)3 = ∛272
∛(x-3)3 = ∛(27⋅27)
(x-3) = ∛(3⋅3⋅3⋅3⋅3⋅3)
x-3 = 9
Add 3 on both sides.
x = 9+3
x = 12
Example 7 :
(x-7)4 = 16
Solution :
Take fourth root on both sides.
x-7 = ∜16
x-7 = ∜(2⋅2⋅2⋅2)
x-7 = 2
Add 7 on both sides.
x = 2+7
x = 9
Example 8 :
3x5/3 + 96 = 0
Solution :
3x5/3 + 96 = 0
Subtract 96 on both sides.
3x5/3 = -96
Divide by 3 on both sides.
x5/3 = -32
Raise power 3 on both sides.
x5 = (-32)3
Take 5th root on both sides.
x = 5√(-32)3
x = 5√((-2)5)3
x = 5√(-2)15
x = ((-2)15)1/5
x = (-2)3
x = -8
Kindly mail your feedback to v4formath@gmail.com
We always appreciate your feedback.
©All rights reserved. onlinemath4all.com
Jul 13, 25 09:51 AM
Jul 13, 25 09:32 AM
Jul 11, 25 08:34 AM