SIMPLIFYING SQUARE ROOTS WORKSHEET

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Simplify the following square root expressions :

1)  โˆš64 + โˆš196

2)  โˆš40 + โˆš160

3)  2โˆš425 - 3โˆš68

4)  โˆš243 - 5โˆš12 + โˆš27

5)  -โˆš117 - โˆš52

6)  (โˆš17)(โˆš51)

7)  (โˆš35)(2โˆš15)

8)  (14โˆš117) รท (7โˆš52)

9)  (7โˆš5)2

10)  (โˆš3)3 + โˆš27

1. Answer :

โˆš64 + โˆš196

Because 64 and 196 are perfect squares, we can find the square root of 64 and 194 as shown below.

โˆš64 = โˆš(8 โ‹… 8)

โˆš64 = 8

โˆš196 = โˆš(14 โ‹… 14)

โˆš196 = 14

โˆš64 + โˆš196 = 8 + 14

= 22

2. Answer :

โˆš40 + โˆš160

Decompose 40 and 160 into prime factors using synthetic division.

โˆš40 = โˆš(2 โ‹… 2 โ‹… 2 โ‹… 5) = 2โˆš10

โˆš160 = โˆš(2 โ‹… 2 โ‹… 2 โ‹… 2 โ‹… 2 โ‹… 5) = 4โˆš10

โˆš40 + โˆš160 :

= 2โˆš10 + 4โˆš10

= 6โˆš10

3. Answer :

2โˆš425 - 3โˆš68

Decompose 425 and 68 into prime factors using synthetic division.

โˆš425 = โˆš(5 โ‹… 5 โ‹… 17)

โˆš425 = 5โˆš17

โˆš68 = โˆš(2 โ‹… 2 โ‹… 17)

โˆš68 = 2โˆš17

2โˆš425 - 3โˆš68 :

= 2(5โˆš17) - 3(2โˆš17)

= 10โˆš17 - 6โˆš17

= 4โˆš17

4. Answer :

โˆš243 - 5โˆš12 + โˆš27

Decompose 243, 12 and 27 into prime factors using synthetic division.

โˆš243 = โˆš(3 โ‹… 3 โ‹… 3 โ‹… 3 โ‹… 3) = 9โˆš3

โˆš12 = โˆš(2 โ‹… 2 โ‹… 3) = 2โˆš3

โˆš27 = โˆš(3 โ‹… 3 โ‹… 3) = 3โˆš3

โˆš243 - 5โˆš12 + โˆš27 :

= 9โˆš3 - 5(2โˆš3) + 3โˆš3

= 9โˆš3 - 10โˆš3 + 3โˆš3

= 2โˆš3

5. Answer :

-โˆš117 - โˆš52

Decompose 117 and 52 into prime factors using synthetic division.

โˆš117 = โˆš(3 โ‹… 3 โ‹… 13) = 3โˆš13

โˆš52 = โˆš(2 โ‹… 2 โ‹… 13) = 2โˆš13

-โˆš117 - โˆš52 :

= -3โˆš13 - 2โˆš13

= -5โˆš13

6. Answer :

(โˆš17)(โˆš51)

Decompose 17 and 51 into prime factors.

Because 17 is a prime number, it can't be decomposed anymore. So, โˆš17 has to be kept as it is.

โˆš51 = โˆš(3 โ‹… 17) = โˆš3 โ‹… โˆš17

(โˆš17)(โˆš51) :

(โˆš17)(โˆš3 โ‹… โˆš17)

= (โˆš17 โ‹… โˆš17)โˆš3

17โˆš3

7. Answer :

(โˆš35)(2โˆš15)

Decompose 35 and 15 into prime factors.

โˆš35 = โˆš(5 โ‹… 7) = โˆš5 โ‹… โˆš7

โˆš15 = โˆš(5 โ‹… 3) = โˆš5 โ‹… โˆš3

(โˆš35)(2โˆš15) :

(โˆš5 โ‹… โˆš7โ‹… 2(โˆš5 โ‹… โˆš3)

= 2(โˆš5 โ‹… โˆš5)(โˆš7 โ‹… โˆš3)

= 2(5)(โˆš(7 โ‹… 3)

= 10โˆš21

8. Answer :

(14โˆš117) รท (7โˆš52)

Decompose 117 and 52 into prime factors using synthetic division.

โˆš117 = โˆš(3 โ‹… 3 โ‹… 13)

โˆš117 = 3โˆš13

โˆš52 = โˆš(2 โ‹… 2 โ‹… 13)

โˆš52 = 2โˆš13

(14โˆš117) รท (7โˆš52) :

= 14(3โˆš13) รท 7(2โˆš13)

= 42โˆš13 รท 14โˆš13

= 42โˆš13/14โˆš13

= 3

9. Answer :

(7โˆš5)= 7โˆš5 โ‹… 7โˆš5

= (7 โ‹… 7)(โˆš5 โ‹… โˆš5)

= (49)(5)

= 245

10. Answer :

(โˆš3)3 + โˆš27 = (โˆš3 โ‹… โˆš3 โ‹… โˆš3) + โˆš(3 โ‹… 3 โ‹… 3)

= (3 โ‹… โˆš3) + 3โˆš3

= 3โˆš3 + 3โˆš3

= 6โˆš3

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