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An expression of the form f(x)/g(x) where f(x) and g(x) are two polynomials over the set of real numbers and g(x) ≠ 0 is called a rational expression.
Examples :
The following steps will be useful to simplify rational expressions.
Step 1 :
Factor both numerator and denominator, if possible.
Step 2 :
Identify the common factors in both numerator and denominator.
Step 3 :
Remove the common factors found in both numerator and denominator.
The following identities can be used to factor the expressions in numerator and denominator.
(a + b)2 = a2 + 2ab + b2
(a - b)2 = a2 - 2ab + b2
a2 - b2 = (a + b)(a - b)
(a + b)3 = a3 + 3a2b + 3ab2 + b2
(a - b)3 = a3 - 3a2b + 3ab2 - b2
a3 + b3 = (a + b)(a2 - ab + b3)
a3 - b3 = (a - b)(a2 + ab + b3)
Simplify each of the following rational expressions :
Example 1 :
4x3/8x2
Solution :
= 4x3/8x2
Here 4 and 8 are divisible by 4, after cancelling the common factor. We get
= x/2
Example 2 :
(5x + 20) / (7x + 28)
Solution :
= (5x + 20) / (7x + 28)
In the numerator, the common factor is 5. At the denominator the common factor is 7. After factoring common factors, we get
= 5(x + 4) / 7(x + 4)
= 5/7
So, the answer is 5/7
Example 3 :
(3x + 9) / (3x + 15)
Solution :
= (3x + 9) / (3x + 15)
Common factor for the numerator is 3 and the common factor for the denominator is also 3.
Factoring it out, we get
= 3(x + 3) / 3(x + 4)
= (x + 3)/(x + 4)
Example 4 :
(x - 3)/(x2 - 9)
Solution :
= (x - 3)/(x2 - 9)
The denominator looks like an algebraic identity a2 - b2
a2 - b2 = (a + b)(a - b)
(x2 - 9) = (x2 - 32)
= (x + 3)(x - 3)
= (x - 3) / (x + 3)(x - 3)
= 1/(x + 3)
Example 5 :
Solution :
= (x2 - 2x + 1)/(x - 1)
(x2 - 2x + 1) = (x - 1)(x - 1)
= (x - 1)(x - 1)/(x - 1)
= (x - 1)
Example 6 :
Solution :
= (x2 + 7x + 10)/(x2 - 4)
= (x + 2)(x + 5) / (x + 2)(x - 2)
= (x + 5) / (x - 2)
Example 7 :
Solution :
= (9x2 - 25y2)/(3x2 - 5xy)
= ((3x)2 - (5y)2)/x(3x - 5y)
= (3x + 5y)(3x - 5y)/x(3x - 5y)
= (3x + 5y)/x
Example 8 :
Solution :
= (6x2 - 54) / (x2 + 7x + 12)
6x2 - 54 = 6(x2 - 9)
= 6(x2 - 32)
= 6(x + 3)(x - 3) -----(1)
(x2 + 7x + 12) = (x + 4)(x + 3) -----(2)
(1) / (2)
= 6(x + 3)(x - 3) / (x + 4)(x + 3)
= 6(x - 3)/(x + 4)
Example 9 :
Solution :
= (2 - x) / (x2 + 4x - 12)
x2 + 4x - 12 = x2 + 6x - 2x - 12
= x(x + 6) - 2(x + 6)
= (x - 2)(x + 6) ------(2)
From the numerator (2 - x), we factor negative.
= -(x - 2) -----(1)
(1) / (2)
= -(x - 2) / (x - 2)(x + 6)
= -1/(x - 6)
Example 10 :
Solution :
= (64a3 + 125b3) / (4a2 b + 5ab2)
Simplifying the numerator :
64a3 + 125b3 = (4a)3 + (5b)3
a3 + b3 = (a + b)(a2 - ab + b2)
(4a)3 + (5b)3 = (4a + 5b) ((4a)2 + (4a)(5b) + (5b)2)
= (4a + 5b) (16a2 + 20ab + 25b2) -----(1)
Simplifying the denominator :
4a2 b + 5ab2 = ab(4a + 5b) -------(2)
(1) / (2)
= (4a + 5b) (16a2 + 20ab + 25b2) / ab(4a + 5b)
= (16a2 + 20ab + 25b2) / ab
Example 11 :
Solution :
= (x4 - 16)/(x2 + 5x + 6)
(x2)2 - 42 = (x2 + 4)(x2 - 4)
= (x2 + 4)(x2 - 22)
= (x2 + 4)(x + 2)(x - 2) ------(1)
x2 + 5x + 6 = x2 + 2x + 3x + 6
= x(x + 2) + 3(x + 2)
= (x + 2)(x + 3) --------(2)
(1) / (2)
= (x2 + 4)(x + 2)(x - 2) / (x + 2)(x + 3)
= (x2 + 4)(x - 2) / (x + 3)
Example 12 :
Solution :
= (v3 + 11v2 + 18v)/(v2 + v - 2)
Simplifying the numerator :
= v(v2 + 11 v + 18)
= v(v2 + 9v + 2v + 18)
= v[v(v + 9) + 2(v + 9)]
= v(v + 2)(v + 9) -------(1)
Simplifying the denominator :
v2 + v - 2 = v2 + 2v - v - 2
= v(v + 2) - 1(v + 2)
= (v - 1)(v + 2) ------(2)
(1) / (2)
= v(v + 2)(v + 9)/(v - 1)(v + 2)
= v(v + 9) / (v - 1)
Example 13 :
Solution :
Example 14 :
Solution :
Example 15 :
Solution :
Example 16 :
Solution :
Example 17 :
Solution :
Example 18 :
Solution :
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