SIMPLIFYING RADICALS WORKSHEET
About "Simplifying Radicals Worksheet"
Simplifying Radicals Worksheet :
Worksheet given in this section is much useful to the students who would like to practice problems on simplifying radicals.
Before look at the worksheet, if you would like to know the basic stuff about simplifying radicals,
Simplifying Radicals Worksheet - Problems
Problem 1 :
Simplify the expression :
√20
Problem 2 :
Simplify the expression :
√121
Problem 3 :
Simplify the expression :
√52
Problem 4 :
Simplify the expression :
√45
Problem 5 :
Simplify the expression :
√72
Problem 6 :
Simplify the expression :
√40
Problem 7 :
Simplify the expression :
√27
Problem 8 :
Simplify the expression :
√243
Problem 9 :
Simplify the expression :
√288
Problem 10 :
Simplify the expression :
√320
Simplifying Radicals Worksheet - Solutions
Problem 1 :
Simplify the expression :
√20
Solution :
Decompose 20 into prime factors using synthetic division.
So, we have
√20 = √(2 ⋅ 2 ⋅ 5)
√20 = 2√5
Problem 2 :
Simplify the expression :
√121
Solution :
Decompose 121 into prime factors.
√121 = √(11 ⋅ 11)
√121 = 11
Problem 3 :
Simplify the expression :
√52
Solution :
Decompose 52 into prime factors using synthetic division.
So, we have
√52 = √(2 ⋅ 2 ⋅ 13)
√52 = 2√13
Problem 4 :
Simplify the expression :
√45
Solution :
Decompose 45 into prime factors using synthetic division.
So, we have
√45 = √(5 ⋅ 3 ⋅ 3)
√45 = 3√5
Problem 5 :
Simplify the expression :
√72
Solution :
Decompose 72 into prime factors using synthetic division.
So, we have
√72 = √(2 ⋅ 2 ⋅ 2 ⋅ 3 ⋅ 3)
√72 = 2 ⋅ 3 ⋅ √2
√72 = 6√2
Problem 6 :
Simplify the expression :
√40
Solution :
Decompose 40 into prime factors using synthetic division.
So, we have
√40 = √(2 ⋅ 2 ⋅ 2 ⋅ 5)
√40 = 2√(2 ⋅ 5)
√40 = 2√10
Problem 7 :
Simplify the expression :
√27
Solution :
Decompose 27 into prime factors using synthetic division.
So, we have
√27 = √(3 ⋅ 3 ⋅ 3)
√27 = 3√3
Problem 8 :
Simplify the expression :
√243
Solution :
Decompose 243 into prime factors using synthetic division.
So, we have
√243 = √(3 ⋅ 3 ⋅ 3 ⋅ 3 ⋅ 3)
√27 = 3 ⋅ 3 ⋅ √3
√27 = 9√3
Problem 9 :
Simplify the expression :
√288
Solution :
Decompose 288 into prime factors using synthetic division.
So, we have
√288 = √(2 ⋅ 2 ⋅ 2 ⋅ 2 ⋅ 2 ⋅ 3)
√288 = 2 ⋅ 2 ⋅ √(2 ⋅ 3)
√288 = 4√6
Problem 10 :
Simplify the expression :
√320
Solution :
Decompose 320 into prime factors using synthetic division.
So, we have
√320 = √(2 ⋅ 2 ⋅ 2 ⋅ 2 ⋅ 2 ⋅ 2 ⋅ 5)
√320 = 2 ⋅ 2 ⋅ 2 ⋅ √5
√320 = 8√5
After having gone through the stuff given above, we hope that the students would have understood, "Simplifying Radicals Worksheet".
Apart from the stuff given in this section, if you need any other stuff in math, please use our google custom search here.
WORD PROBLEMS
HCF and LCM word problems
Word problems on simple equations
Word problems on linear equations
Word problems on quadratic equations
Area and perimeter word problems
Word problems on direct variation and inverse variation
Word problems on comparing rates
Converting customary units word problems
Converting metric units word problems
Word problems on simple interest
Word problems on compound interest
Word problems on types of angles
Complementary and supplementary angles word problems
Markup and markdown word problems
Word problems on mixed fractrions
One step equation word problems
Linear inequalities word problems
Ratio and proportion word problems
Word problems on sets and venn diagrams
Pythagorean theorem word problems
Percent of a number word problems
Word problems on constant speed
Word problems on average speed
Word problems on sum of the angles of a triangle is 180 degree
OTHER TOPICS
Time, speed and distance shortcuts
Ratio and proportion shortcuts
Domain and range of rational functions
Domain and range of rational functions with holes
Graphing rational functions with holes
Converting repeating decimals in to fractions
Decimal representation of rational numbers
Finding square root using long division
L.C.M method to solve time and work problems
Translating the word problems in to algebraic expressions
Remainder when 2 power 256 is divided by 17
Remainder when 17 power 23 is divided by 16
Sum of all three digit numbers divisible by 6
Sum of all three digit numbers divisible by 7
Sum of all three digit numbers divisible by 8
Sum of all three digit numbers formed using 1, 3, 4
Sum of all three four digit numbers formed with non zero digits
