Problem 1 :
Simplify :
√(16u4v3)
Problem 2 :
Simplify :
√(147m3n3)
Problem 3 :
Simplify :
3√(125p6q3)
Problem 4 :
Simplify :
4√(x4/16)
Problem 5 :
Simplify :
6√(72y2)
Problem 6 :
Simplify :
√(196a6b8c10)
Problem 7 :
Simplify :
√[(x + 11)2 - 44x]
Problem 8 :
Simplify :
√(121x8y6 ÷ 81x4y8)
Problem 9 :
Simplify :
√(16x2 - 24x + 9)
Problem 10 :
Simplify :
√[x2 + (1/x2) + 2]
Problem 1 :
Simplify :
√(16u4v3)
Solution :
√(16u4v3) = √(4 ⋅ 4 ⋅ u2 ⋅ u2 ⋅ v ⋅ v ⋅ v)
√(16u4v3) = 4u2v√v
Problem 2 :
Simplify :
√(147m3n3)
Solution :
√(147m3n3) = √(7 ⋅ 7 ⋅ 3 ⋅ m ⋅ m ⋅ m ⋅ n ⋅ n ⋅ n)
√(147m3n3) = 7mn√(3mn)
Problem 3 :
Simplify :
3√(125p6q3)
Solution :
3√(125p6q3) = 3√(5 ⋅ 5 ⋅ 5 ⋅ p2 ⋅ p2 ⋅ p2 ⋅ q ⋅ q ⋅ q)
3√(125p6q3) = 5p2q
Problem 4 :
Simplify :
4√(x4/16)
Solution :
4√(x4/16) = 4√(x4) / 4√16
4√(x4/16) = 4√(x ⋅ x ⋅ x ⋅ x) / 4√(2 ⋅ 2 ⋅ 2 ⋅ 2)
4√(x4/16) = x / 2
Problem 5 :
Simplify :
6√(72y2)
Solution :
6√(72y2) = 6√(6 ⋅ 6 ⋅ 2 ⋅ y ⋅ y)
6√(72y2) = 6(6y)√2
6√(72y2) = 12y√2
Problem 6 :
Simplify :
√(196a6b8c10)
Solution :
√(196a6b8c10) = √(14 ⋅ 14 ⋅ a3 ⋅ a3 ⋅ b4 ⋅ b4 ⋅ c5 ⋅ c5)
√(196a6b8c10) = 14a3b4c5
Problem 7 :
Simplify :
√[(x + 11)2 - 44x]
Solution :
√[(x + 11)2 - 44x] = √[x2 + 2(x)(11) + 112 - 44x]
√[(x + 11)2 - 44x] = √[x2 + 22x + 121 - 44x]
√[(x + 11)2 - 44x] = √[x2 - 22x + 121]
√[(x + 11)2 - 44x] = √[(x - 11)(x - 11)]
√[(x + 11)2 - 44x] = x - 11
Problem 8 :
Simplify :
√(121x8y6 ÷ 81x4y8)
Solution :
√(121x8y6 ÷ 81x4y8) = √(121x8y6 / 81x4y8)
√(121x8y6 ÷ 81x4y8) = √(121x8-4 / 81y8-6)
√(121x8y6 ÷ 81x4y8) = √(121x4 / 81y2)
√(121x8y6 ÷ 81x4y8) = √(112x4 / 92y2)
√(121x8y6 ÷ 81x4y8) = 11x2 / 9y
Problem 9 :
Simplify :
√(16x2 - 24x + 9)
Solution :
√(16x2 - 24x + 9) = √[42x2 - 2(4x)(3) + 32]
√(16x2 - 24x + 9) = √[(4x)2 - 2(4x)(3) + 32]
Using the algebraic identity (a - b)2 = a2 - 2ab + b2 on the right side,
√(16x2 - 24x + 9) = √(4x - 3)2
√(16x2 - 24x + 9) = (4x - 3)
Problem 10 :
Simplify :
√[x2 + (1/x2) + 2]
Solution :
√[x2 + (1/x2) + 2] = √[x2 + 2 + (1/x2)]
√[x2 + (1/x2) + 2] = √[x2 + 2(x)(1/x) + (1/x)2]
Using the algebraic identity (a + b)2 = a2 + 2ab + b2 on the right side,
√[x2 + (1/x2) + 2] = √(x2 + 2(x)(1/x) + (1/x)2]
√[x2 + (1/x2) + 2] = √(x + 1/2)2
√[x2 + (1/x2) + 2] = x + 1/2
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