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Case 1 :
If the denominator is in the form of āb (where b is a rational number), then we have to multiply both the numerator and denominator by the same āb to rationalize the denominator.
Case 2 :
If the denominator is in the form of a ± āb or a ± cāb (where b is a rational number), then we have to multiply both the numerator and denominator by its conjugate.
a + āb and a - āb are conjugate to each other
a + cāb and a - cāb are conjugate to each other
Case 3 :
If the denominator is in the form of āa ± āb (where a and b are rational numbers), then we have to multiply both the numerator and denominator by its conjugate.
āa + āb and āa - āb are conjugate to each other
Example 1 :
Simplify :
18 / ā6
Solution :
Simplifying the above radical expression is nothing but rationalizing the denominator.
So, rationalize the denominator.
Here, the denominator is ā6.
In the given fraction, multiply both numerator and denominator by ā6.
18 / ā6 = (18ā6) / (ā6 ā ā6)
18 / ā6 = 18ā6 / 6
18 / ā6 = 3ā6
Example 2 :
Simplify :
1 / (2 + ā5)
Solution :
Simplifying the above radical expression is nothing but rationalizing the denominator.
So, rationalize the denominator.
Here, the denominator is 2 + ā5.
In the given fraction, multiply both numerator and denominator by the conjugate of 2 + ā5. That is 2 - ā5.

Example 3 :
Simplify :
(6 + ā5) / (6 - ā5)
Solution :
Simplifying the above radical expression is nothing but rationalizing the denominator.
So, rationalize the denominator.
Here, the denominator is 6 - ā5.
In the given fraction, multiply both numerator and denominator by the conjugate of 6 - ā5. That is 6 + ā5.
(6 + ā5) / (6 - ā5) = [(6+ā5)(6+ā5)] / [(6-ā5)(6+ā5)]
(6 + ā5) / (6 - ā5) = [(6+ā5)(6+ā5)] / [(6-ā5)(6+ā5)]
(6 + ā5) / (6 - ā5) = (6 + ā5)2 / [62 - (ā5)2]
(6 + ā5) / (6 - ā5) = [62 + 2(6)(ā5) + (ā5)2] / (36 - 5)
(6 + ā5) / (6 - ā5) = [36 + 12ā5 + 5] / 31
(6 + ā5) / (6 - ā5) = (41 + 12ā5) / 31
Example 4 :
Find the values of 'x' and 'y' :
(2 + ā3)/(2 - ā3) = x + yā3
Solution :
(2 + ā3)/(2 - ā3) = x + yā3
On the left side of the above equation, multiply both numerator and denominator by the conjugate of 2 - ā3. That is 2 + ā3.
[(2+ā3)(2+ā5)] / [(2-ā3)(2+ā3)] = x + yā3
(2 + ā3)2 / [22 - (ā3)2] = x + yā3
[22 + 2(2)(ā3) + (ā3)2] / (4 - 3) = x + yā3
[4 + 4ā3 + 3] / 1 = x + yā3
7 + 4ā3 = x + yā3
Therefore,
x = 7
y = 4
Example 5 :
Simplify :
ā(12x2) / ā(30x)
Solution :
ā(12x2) / ā(30x) = ā(12x2/30x)
ā(12x2) / ā(30x) = ā(2x/5)
ā(12x2) / ā(30x) = ā(2x) / ā5
On the right side, multiply both numerator and denominator by ā5.
ā(12x2) / ā(30x) = ā(2x) ā ā5 / ā5 ā ā5
ā(12x2) / ā(30x) = ā(2x ā 5) / 5
ā(12x2) / ā(30x) = ā10x / 5
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