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To simplify algebraic expression, first we have to be clear with like and unlike terms.
Like Terms :
Like terms are terms that have the same variables with the same exponents.
Terms that are not like terms in unknown as unlike terms.

|
Let us assume |
Day 1 |
Day 2 |
|
a = 1 kg of potato b = 1 kg of onion c = 1 kg of tomatoes d = 1 kg of lady fingers |
3a 7b 8c 0d |
4a 0b 2c 3d |
= (3a + 4a) + (7b + 0b) + (8c + 2c) + (0d + 3d)
= 7a + 7b + 10c + 3d
So, 7 kg of potatoes, 7 kg of onion, 10 kg of tomatoes and 3 kg of lady fingers.
Simplify the following expression :
Problem 1 :
3x2 โ x + 6 + x2 + 3x
Solution :
= 3x2 โ x + 6 + x2 + 3x
By grouping the like terms, we get
= (3x2 + x2) + (3x โ x) + 6
By combining the like terms, we get
= 4x2 + 2x + 6
Problem 2 :
2a โ 3b + 4 โ a + 1
Solution :
= 2a โ 3b + 4 โ a + 1
By grouping the like terms, we get
= (2a โ a) โ 3b + (4 + 1)
By combining the like terms, we get
= a โ 3b + 5
Problem 3 :
2c โ c2 + 3c + 1
Solution :
= 2c โ c2 + 3c + 1
By grouping the like terms, we get
= (2c + 3c) โ c2 + 1
By combining the like terms, we get
= -c2 + 5c + 1
Problem 4 :
2c + cd โ 4c + dc โ 4d
Solution :
= 2c + cd โ 4c + dc โ 4d
= (2c โ 4c)
+ (cd + dc) โ 4d
= 2cd โ 2c โ 4d
Problem 6 :
5x โ 10y + 6x
Solution :
= 5x โ 10y + 6x
= (5x + 6x) โ 10y
= 11x โ 10y
Problem 7 :
5 โ m + 5r โ m
Solution :
= 5 โ m + 5r โ m
= 5r -m -m + 5
= 5r โ 2m + 5
Problem 8 :
6ac + 6a โ 4c
Solution :
= 6ac + 6a โ 4c
There is no like terms.
Problem 9 :
7e - 8f โ 2e + 5f
Solution :
= 7e - 8f โ 2e + 5f
= (7e โ 2e) + (5f-8f)
= 5e โ
3f
Problem 10 :
8x ยท 5
Solution :
= 8x ยท 5
= 40x
Problem 11 :
(a โ c) x 7
Solution :
= (a โ c) ยท 7
= 7a โ 7c
Problem 12 :
3 x a x a x b x b x b
Solution :
= 3 x a x a x b x b x b
a is repeated 2 times and b is repeated 3 times.
= 3a2b3
Problem 13 :
2 ยท x + x ยท x + x ยท x ยท x
Solution :
2 ยท x + x ยท x + x ยท x ยท x
= 2x + x2 + x3
Problem 14 :
2x2 x 3x
Solution :
= 2x2 x 3x
= 6x3
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