SET THEORY PRACTICE WORKSHEET FOR GRADE 11

About "Set Theory Practice Worksheet For Grade 11"

Set Theory Practice Worksheet For Grade 11 :

Here we are going to see some practice questions on set theory.

(1)  Write the following in roster form.

(i) {x ∈ N : x² < 121 and x is a prime}.     Solution

(ii) the set of all positive roots of the equation (x − 1)(x + 1)(x² − 1) = 0.     Solution

(iii)  {x ∈ N : 4x + 9 < 52}.     Solution

(iv)  {x : (x−4)/(x+2) = 3, x ∈ R − {−2}}.     Solution

(2)  Write the set {−1, 1} in set builder form.       Solution

(3)  State whether the following sets are finite or infinite.

(i) {x ∈ N : x is an even prime number}.      Solution

(ii) {x ∈ N : x is an odd prime number}.      Solution

(iii) {x ∈ Z : x is even and less than 10}.      Solution

(iv) {x ∈ R : x is a rational number}.      Solution

(v) {x ∈ N : x is a rational number}.      Solution

(4)  By taking suitable sets A,B,C, verify the following results:

(i) A × (B ∩ C) = (A × B) ∩ (A × C).      Solution

(ii) A × (B ∪ C) = (A × B) ∪ (A × C)         Solution

(iii) (A × B) ∩ (B × A) = (A ∩ B) × (B ∩ A)       Solution

(iv) C − (B − A) = (C ∩ A) ∪ (C ∩ B').       Solution

(v) (B − A) ∩ C = (B ∩ C) − A = B ∩ (C − A).       Solution

(vi) (B − A) ∪ C = (B ∪ C) − (A − C)       Solution

(5)  Justify the trueness of the statement:

“An element of a set can never be a subset of itself.”

Solution

(6)  If n(P(A)) = 1024, n(A ∪ B) = 15 and n(P(B)) = 32, then find n(A ∩ B).                Solution

(7)  If n(A ∩ B) = 3 and n(A ∪ B) = 10, then find n(P(AΔB)).             Solution

(8)  For a set A, A × A contains 16 elements and two of its elements are (1, 3) and (0, 2). Find the elements of A.

Solution

(9)  Let A and B be two sets such that n(A) = 3 and n(B) = 2. If (x, 1), (y, 2), (z, 1) are in A × B, find A and B, where x, y, z are distinct elements.             Solution

(10)  If A × A has 16 elements, S = {(a, b) ∈ A × A : a < b} ; (−1, 2) and (0, 1) are two elements of S, then find the remaining elements of S.             Solution

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