## SECTION FORMULA INTERNALLY AND EXTERNALLY

We use the section formula to find the point which divides the line segment in a given ratio.

The point P which divides the line segment joining the two points A (x1,  y1) and B (x2, y2) internally in the ratio l : m is

If P divides a line segment AB joining the two points

A (x1,  y1) and B (x2, y2) externally in the ratio l : m is,

Example 1 :

Find the coordinates of the point which divides the line segment joining (-3, 5) and (4, -9) in the ratio 1:6 internally.

Solution :

Let  A (-3, 5) and B (4, -9)

Section formula internally

=  (lx2+mx1)/(l+m),  (ly2+my1)/(l+m)

l = 1 and m = 6

=  [(1(4)+(6(-3)]/(1+6) , [(1(-9)) + 6(5)]/(1+6)

=  (4-18)/7, (-9 + 30)/7

=  -14/7, 21/7

=  (-2, 3)

Example 2 :

Let A (-6 , -5) and B(-6 , 4) be the two points such that a point  P on the line AB satisfies AP = (2/9) AB.

Find the point P.

Solution :

AP  =  (2/9) AB

9AP  =  2(AP+PB)

9AP  =  2AP + 2PB

9AP – 2AP  =  2PB

7AP  =  2PB

AP/AB  =  2/7

AP:PB  =  2:7

So P divides the line segment in the ratio 2:7

Section formula internally

(lx2+mx1)/(l+m),  (ly2+my1)/(l+m)

l = 2, m = 7

=  [(2(-6)+7(-6)]/(2+7), [(2x(4)+7(-5)]/(2+7)

=  (-12-42)/9, (8-35)/9

=  -54/9, -21/7

=  (-6, -3)

Example 3 :

Find the points of trisection of the line segment joining the points A (2, -2) and B (-7, 4).

Solution :

AP = 1, PQ = 1, QB = 1

(lx2+mx1)/(l+m),  (ly2+my1)/(l+m)

P divides the line segment in the ratio 1:2

l = 1, m = 2

=  [(1(-7)+2(2)]/(1+2),  [1(4)+2(-2)]/(1+2)

=  (-7+4)/3, (4-4)/3

=  -3/3 , 0/3

=  P (-1 , 0)

Q divides the line segment in the ratio 2:1

l = 2, m = 1

=  [2(-7)+1(2)]/(2+1), [2(4)+1(-2)]/(2+1)

=  (-14+2)/3, (8-2)/3

=  -12/3 , 6/3

=  Q (-4, 2)

Example 4 :

Find the ratio in which x axis divides the line segment joining the points (6, 4) and (1,- 7).

Solution :

Let l : m be the ratio of the line segment joining the points (6, 4) and (1, -7) and let p(x, 0) be the point on the x axis

Section formula internally

(lx2+mx1)/(l+m),  (ly2+my1)/(l+m)

(x, 0)  =  [l(1)+m(6)]/(l+m) , [l(-7)+m(4)]/(l+m)

(x , 0)  =  [l+6m]/(l+m) , [-7l+4m]/(l+m)

Equating y-coordinates

[-7l+4m]/(l+m)  =  0

-7l+4m  =  0

-7l  =  -4m

l/m  =  4/7

l : m = 4 : 7

So, x-axis divides the line segment in the ratio 4:7.

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