Evaluate each of the following.
1) √4
2) √16
3) √64
4) √144
5)3√27
6) 3√-8
7) 3√512
8) 3√-8000
9) 4√64
10) 4√81
11) 5√32
12) 5√243
13) √8
14) √45
15) 3√54
16) √25 + √36
17) √20 + √45
18) 2√18 - √8
19) 3√8 + 3√27
20) √49 + 3√125 + 4√256
Simplify the radicals :
21) √7(6 - √7)
22) 8√7 (4√5 + 6√3)
23) (5 + √7) (7 - √2)
1. Answer :
Step 1 :
First we write the given number which is inside the radical as product of prime numbers.
√4 = √(2 x 2)
Step 2 :
Since we have two same numbers inside the radical, we can take one term out of the radical.
= 2
2. Answer :
Step 1 :
First we write the number which is inside the radical as product of prime factors.
√16 = √(2 x 2 x 2 x 2)
Step 2 :
For every two 2's, we have to take one 2 out of the square root sign.
= 2 x 2
= 4
3. Answer :
Step 1 :
First we write the number which is inside the radical as product of prime factors.
√64 = √(2 x 2 x 2 x 2 x 2 x 2)
Step 2 :
For every two 2's, we have to take one 2 out of the square root sign.
= 2 x 2 x 2
= 8
4. Answer :
Step 1 :
First we write the number which is inside the radical as product of prime factors.
√144 = √(2 x 2 x 2 x 2 x 3 x 3)
Step 2 :
√144 = 2 x 2 x 3
= 12
5. Answer :
Step 1 :
First we write the number which is inside the radical as product of prime factors.
3√27 = √(3 x 3 x 3)
Step 2 :
3√27 = 3
6. Answer :
Writing -8 as product of prime factors.
3√-8 = 3√[(-2)(-2)(-2)]
Since we have three same values which are multiplied inside the cube root sign, we can take one -2 out of the cube root sign.
= -2
7. Answer :
3√512 = 3√(2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2)
For every three same values inside the cube root sign, we can take one value out of the cube root sign.
= 2 x 2 x 2
= 8
8. Answer :
Sicne we have negative sign inside the cube root sign, the answer will also have negative sign.
3√-8000 = 3√[(2 x 2 x 5 x 2 x 2 x 5 x 2 x 2 x 5)
= -(2 x 2 x 5)
= -20
9. Answer :
4√64 = 4√(2 x 2 x 2 x 2 x 2 x 2)
Sicne we have fourth root, we have to one value out of the fourth root sign
= 2 x 2
4√64 = 4
10. Answer :
4√81 = 4√(3 x 3 x 3 x 3)
Since we have fourth root, we have to one value out of the fourth root sign
= 3
11. Answer :
5√32 = 5√(2 x 2 x 2 x 2 x 2)
Since we have fifth root, we have to one value out of the fifth root sign
= 2
12. Answer :
5√243 = 5√(3 x 3 x 3 x 3 x 3)
Since we have fifth root, we have to one value out of the fifth root sign
= 3
13. Answer :
√8 = √(2 x 2 x 2)
= 2√2
14. Answer :
√45 = √(3 x 3 x 5)
We can take one value out of the square root sign.
= 3√5
15. Answer :
3√54 = 3√(3 x 3 x 3 x 2)
= 33√2
16. Answer :
√25 + √36 = √(5 x 5) + √(6 x 6)
= 5 + 6
= 11
17. Answer :
√20 + √45 = √(2 x 2 x 5) + √(3 x 3 x 5)
= 2√5 + 3√5
= 5√5
18. Answer :
2√18 - √8 = 2√(3 x 3 x 2) - √(2 x 2 x 2)
= 2(3√2) - 2√2
= 6√2 - 2√2
= 4√2
19. Answer :
3√8 + 3√27 = 3√(2 x 2 x 2) + 3√(3 x 3 x 3)
= 2 + 3
= 5
20. Answer :
√49 + 3√125 + 4√256 :
= √(7 x 7) + 3√(5 x 5 x 5) + 4√(4 x 4 x 4 x 4)
= 7 + 5 + 4
= 16
21. Answer :
√7(6 - √7)
Using distributive property,
= 6√7 - √7√7
= 6√7 - 7
22. Answer :
= 8√7 (4√5 + 6√3)
Using distributive property,
= 8√7 (4√5) + 8√7 (6√3)
= 32√(7 x 5) + 48√(7 x 3)
= 32√35 + 48√21
23. Answer :
(5 + √7) (7 - √2)
Using distributive property,
= (5 + √7) (7 - √2)
= 5(7) - 5√2 + 7√7 - √2(√7)
= 35 - 5√2 + 7√7 - √14
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