REDUCING FRACTIONS TO LOWEST TERMS EXAMPLES

Reducing Fractions to Lowest Terms Examples :

In this section, you will learn, how to reduce a fraction to its lowest term.

To reduce a fraction to its lowest term, we need to divide both numerator and denominator by the same number as much as possible.

We can use the divisibility rules to find the common divisor of both numerator and denominator. 

Reducing Fractions to Lowest Terms Examples

Example 1 :

Simplify :

16/24

Solution :

In the given fraction, both numerator and denominator are divisible by 8. 

So, we can divide both numerator and denominator by 8.

16/24  =  (16 ÷ 8) / (24 ÷ 8)

16/24  =  2/3

Example 2 :

Simplify : 

15/18

Solution :

In the given fraction, both numerator and denominator are divisible by 3. 

So, we can divide both numerator and denominator by 3.

15/18  =  (15 ÷ 3) / (18 ÷ 6)

15/18  =  5/6

Example 3 :

Simplify : 

30/48

Solution :

In the given fraction, both numerator and denominator are divisible by 6. 

So, we can divide both numerator and denominator by 6.

30/48  =  (30 ÷ 6) / (48 ÷ 6)

30/48  =  5/8

Example 4 :

Simplify : 

12/40

Solution :

In the given fraction, both numerator and denominator are divisible by 4. 

So, we can divide both numerator and denominator by 4.

12/40  =  (12 ÷ 4) / (40 ÷ 4)

12/40  =  3/10

Example 5 :

Simplify : 

15/51

Solution :

In the given fraction, both numerator and denominator are divisible by 3. 

So, we can divide both numerator and denominator by 3.

15/51  =  (15 ÷ 3) / (51 ÷ 3)

15/51  =  5/17

Example 6 :

Simplify :

14/49

Solution :

In the given fraction, both numerator and denominator are divisible by 7. 

So, we can divide both numerator and denominator by 7.

14/49  =  (14 ÷ 7) / (49 ÷ 7)

14/49  =  2/7

After having gone through the stuff given above, we hope that the students would have understood, how to reduce a fraction to its lowest term using divisibility rules. 

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