(1) Make y the subject of :
2x + 5y = 10
(2) Solve for x :
3x + a = d
(3) Solve for x :
5x + 2y = d
(4) Make a the subject of F = ma
(5) Make d the subject of V = ldh
(6) Make h the subject of A = bh/2
(7) Rearrange this formula into the form y = mx + c.
Hence, state the value of :
a) the slope m
b) the y-intercept c.
(8) Make t the subject of s = (1/2) gt2, where t > 0.
(9) Make x the subject of y = (3x+2)/(x-1)
(10) Make y the subject of M = 4/(x2+y2)
(11)
A = 180(n - 2)/n
The formula above shows the relationship between A, the measure of each angle of a regular polygon, and n, the number of sides of a regular polygon
Which of the following expresses the number of sides in terms of the measure of an angle?
a) n = (A - 180)/360 b) n = (A/360) - 2
c) n = 180A - (1/2) d) n = 360/(180 - A)
12) If p, q, r, and s are four different positive numbers such that
p = r/(s - r) and q = r/s
What is q in terms of s ?
a) 1 + (1/p) b) 1 - (1/p) c) 1/(1 + p) d) p/(1+p)
13)
Mosteller's formula A = √hw/60
Current's formula A = (4 + w)/30
The formulas are used in medicine to estimate the body surface area A, in square meters, of infants and children whose weight w ranges between 3 and 30 kilograms and whose height h is measured in centimeters.
a) Based on Current's formula, what is w in terms of A
b) If Mosteller's and Current's formula give the same estimate for A, which of the following expression is equivalent to √hw
a) (4 + w)/2 b) (4 + w)/1800 c) 2(4 + w)
d) (4 + w)2/2
14) The formula below is often used by the project managers to compute E, the estimated time to complete a job. Where O is the shortest completion time, P is the longest completion time and M is the most likely completion time.
E = (O + 4M + P)/6
Which of the following correctly gives P in terms of E, O and M ?
a) P = 6E - O - 4M b) P = -6E + O + 4M
c) P = (O + 4M + E)/6 d) P = (O + 4M - E)/6
(1) Solution :
Solving the equation for y, we get
5y = 10-2x
Divide by 5 on both sides, we get
y = (10-2x)/5
y = 2 - (2x/5)
(2) Solution :
3x = d-a
x = (d-a)/3
(3) Solution :
5x = d-2y
x = (d-2y)/5
(4) Solution :
F = ma
a = F/m
(5) Solution :
V = ldh
d = V/lh
(6) Solution :
A = bh/2
h = 2A/b
(7) Solution :
y = mx + c
(a) Solve the formula for m :
mx = y - c
m = (y-c)/x
(b) Solving for c :
c = y-mx
(8) Solution :
s = (1/2) gt2
2s = gt2
t2 = 2s/g
t = √(2s/g)
(9) Solution :
y = (3x+2)/(x-1)
y(x-1) = 3x+2
xy-y = 3x+2
xy-3x = 2+y
x(y-3) = 2+y
x = (2+y)/(y-3)
(10) Solution :
M = 4/(x2+y2)
x2+y2 = 4/M
y2 = (4/M) - x2
y = √[(4/M) - x2]
(11) Solution :
A = 180(n - 2)/n
Here we have to solve for n,
An = 180(n - 2)
An = 180n - 360
Adding 360 on both sides,
360 = 180 n - A n
360 = n(180 - A)
Dividing by 180 - A on both sides,
360 / (180 - A) = n
So, option d is correct.
12) Solution :
p = r/(s - r) and q = r/s
Solving for r from the above information, we get
r = p(s - r) -----(1)
r = qs ------(2)
p(s - r) = qs
ps - pr = qs
Dividing by s on both sides
ps/s - pr/s = q
p - p(r/s) = q
Applying the value of r/s = q, we get
p - pq = q
p = q + pq
p = q(1 + p)
q = p/(1 + p)
13) Solution :
So, option d is correct.
Mosteller's formula A = √hw/60 ----(1)
Current's formula A = (4 + w)/30 ---(2)
a) For this, we have to solve for w in terms of A.
Multiplying by 30 on both sides
30A = 4 + w
Subtracting 4 on both sides
w = 30A - 4
b)
Mosteller's formula A = √hw/60 ----(1)
Current's formula A = (4 + w)/30 ---(2)
(1) = (2)
√hw/60 = (4 + w)/30
√hw = 60 [(4 + w)/30]
√hw = 2 (4 + w)
14) Solution :
E = (O + 4M + P)/6
Here we have to solve for P, we get
6E = O + 4M + P
Subtracting O and 4M on both sides.
6E - O - 4M = P
So, P = 6E - O - 4M
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