In this page quadrant we are going to see the how to find area and perimeter of any this shape.

A quad-rant is exactly one fourth of any circle.

Area of quad-rant = (1/4) Π r²

A quad-rant has 90 degree at the center.

Example 1:

Solution:

Here r = 7 cm and Π = 22/7

= (1/4) x (22/7) x (7)²

= (1/4) x (22/7) x 7 x 7

= (1/4) x 22 x 7

= (1/2) x 11 x 7

= 11 x 3.5

= 38.5 cm²

Example 2:

Area of quad-rant = (1/4) Π r²

Solution:

Here r = 3.5 cm and Π = 22/7

= (1/4) x (22/7) x (3.5)²

= (1/4) x (22/7) x 3.5 x 3.5

= (1/4) x 22 x 0.5 x 3.5

= (1/2) x 11 x 0.5 x 3.5

= 10.5 x 0.5 x 3.5

= 18.375 cm²

Example 3:

Area of quad-rant = (1/4) Π r²

Here r = 3.5 cm and Π = 22/7

= (1/4) x (22/7) x (64)²

= (1/4) x (22/7) x 64 x 64

=  (22/7) x 16 x 64

= (22 x 16 x 64)/7

= 22528/7

= 3218.28 cm²

Perimeter of a quad-rant = Πr/2

Now let us see some example problems based on this formula.

Example 1:

Solution:

Perimeter of a quad-rant = Πr/2

Here r = 7 cm and  Π = 22/7

= [(22/7) x 7]/2

= 22/2

= 11 cm

Example 2:

Solution:

Perimeter of a quadrant = Πr/2

Here r = 4.2 cm and  Π = 22/7

= [(22/7) x 4.2]/2

= (22 x 0.6)/2

= (11 x 0.6)

= 6.6 cm

Example 3:

Solution:

Perimeter of a quad-rant = Πr/2

Here r = 14 cm and  Π = 22/7

= [(22/7) x 14]/2

= (22 x 2)/2

= (44/2)

= 22 cm

Related Topics