PSAT Practice Questions Math :
Here we are going to see a some practice questions for PSAT exams.
Please visit the page "PSAT Math Questions and Answers" to find thefirst 10 questions.
PSAT Practice Questions Math :
Question 11 :
Since we have even power, so the negative sign will become positive.
= (39 ⋅ 39) / (13 ⋅ 13 ⋅ 13)
= (3 ⋅ 3) / 13
Question 12 :
In a scaled diagram, 1 inch represents 20 feet. How many square inches on the diagram represent 1 square foot ?
1 inch = 20 feet
1 feet = 1/20 inch
1 square foot = (1/20)2
Hence 0.0025 square inches represents 1 square foot.
Question 13 :
What is the greatest common factor of 2,240 and 3,360 ?
To find the greatest common factor, we have to decompose the numbers by the prime factor until we get prime numbers.
Greatest common factor = 5 ⋅ 2 ⋅ 2 ⋅ 2 ⋅ 2 ⋅ 2 ⋅ 7
Question 14 :
If 50% of 2y is 12, what is y2 ?
50% of 2y = 12
(50/100) ⋅ (2y) = 12
(1/2) ⋅ (2y) = 12
y = 12
y2 = 122 ==> 144
Hence the value of y2 is 144.
Question 15 :
(15) In the figure given below ∢ PRL is 150 degree. What is (a2 - b2)/(a - b) ?
To find the value of (a2 - b2)/(a - b), first let us simplify this using algebraic identities.
(a2 - b2)/(a - b) = (a + b)(a - b)/(a - b)
(a2 - b2)/(a - b) = a + b
From the given picture, we have
<PRL = 150
<PRL = <RPQ + <PQR
150 = a + b
Hence the value of a + b is 150.
Question 16 :
If y = 3/4 and xy2 = 9/16, what is (x - 4)?
Given that :
y = 3/4 and xy2 = 9/16
x(3/4)2 = 9/16
x(9/16) = 9/16
x = 1
then x - 4 = 1 - 4 = -3
Hence the value of x - 4 is -3
Question 17 :
If P is an odd integer, which of the following must be an even number ?
By observing the options, D is having an even number in the denominator. So we might have even number in the numerator.
Even number / even number = even number
Hence (2p2 - 2P3) / 2P is the even number.
Question 18 :
If the diameter of a circle is P, and P2/4 = 2, what is the area of the circle ?
Diameter of the circle = P
Radius of the circle = P/2
Area of the circle = π r2
= π (P/2)2
= π (P2/4)
Hence the required area of the circle is 2π.
Question 19 :
If a regular polygon has (N - 10) sides, where, N = (40/10)2, what is the measure of one of its angles?
N = (40/10)2 ==> 42 = 16
Number of sides in the given polygon
N - 10 ==> 16 - 10 = 6
So, the given polygon has 6 sides, it is hexagon.
Sum of the angles of a polygon = (n - 2) 180
= (6 - 2) 180
= 4 (180)
Angle measure = 720/6
= 120 degree
Question 20 :
If the perimeter of the triangle shown above is the circumference of a circle, then what is the radius of the circle?
Perimeter of triangle = Sum of lengths of all sides
Let "x" be the length of unknown side.
(5π)2 = (4π)2 + x2
25π2 - 16π2 = x2
x2 = 9π2
x = 3π
Perimeter of triangle = 3π + 5π + 4π
Circumference of circle = 12 π
2π r = 12π
r = 6
Hence the radius of circle is 6
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