PSAT Practice Questions Math :
In this section, we are going to see some PSAT math practice questions.
Please visit the page "PSAT Math Questions and Answers" to find thefirst 10 questions.
PSAT Practice Questions Math :
Question 11 :
Since we have even power, so the negative sign will become positive.
= (39 ⋅ 39) / (13 ⋅ 13 ⋅ 13)
= (3 ⋅ 3) / 13
Question 12 :
In a scaled diagram, 1 inch represents 20 feet. How many square inches on the diagram represent 1 square foot ?
1 inch = 20 feet
1 feet = 1/20 inch
1 square foot = (1/20)2
Hence 0.0025 square inches represents 1 square foot.
Question 13 :
What is the greatest common factor of 2,240 and 3,360 ?
To find the greatest common factor, we have to decompose the given numbers into the prime factors until we get prime numbers.
To find the greatest common divisor, take all the common divisors of 2240 and 3360 and multiply them.
Greatest common factor = 5 ⋅ 2 ⋅ 2 ⋅ 2 ⋅ 2 ⋅ 2 ⋅ 7
Question 14 :
If 50% of 2y is 12, what is y2 ?
50% of 2y = 12
(50/100) ⋅ (2y) = 12
(1/2) ⋅ (2y) = 12
y = 12
y2 = 122 ==> 144
Hence the value of y2 is 144.
Question 15 :
(15) In the figure given below ∢ PRL is 150 degree. What is (a2 - b2)/(a - b) ?
To find the value of (a2 - b2)/(a - b), first let us simplify this using algebraic identities.
(a2 - b2)/(a - b) = (a + b)(a - b)/(a - b)
(a2 - b2)/(a - b) = a + b
From the given picture, we have
<PRL = 150
<PRL = <RPQ + <PQR
150 = a + b
Hence the value of a + b is 150.
Question 16 :
If y = 3/4 and xy2 = 9/16, what is (x - 4)?
Given that :
y = 3/4 and xy2 = 9/16
x(3/4)2 = 9/16
x(9/16) = 9/16
x = 1
then x - 4 = 1 - 4 = -3
Hence the value of x - 4 is -3
Question 17 :
If P is an odd integer, which of the following must be an even number ?
By observing the options, D is having an even number in the denominator. So we might have even number in the numerator.
Even number / even number = even number
Hence (2p2 - 2P3) / 2P is the even number.
Question 18 :
If the diameter of a circle is P, and P2/4 = 2, what is the area of the circle ?
Diameter of the circle = P
Radius of the circle = P/2
Area of the circle = π r2
= π (P/2)2
= π (P2/4)
Hence the required area of the circle is 2π.
Question 19 :
If a regular polygon has (N - 10) sides, where, N = (40/10)2, what is the measure of one of its angles?
N = (40/10)2 ==> 42 = 16
Number of sides in the given polygon
N - 10 ==> 16 - 10 = 6
So, the given polygon has 6 sides, it is hexagon.
Sum of the angles of a polygon = (n - 2) 180
= (6 - 2) 180
= 4 (180)
Angle measure = 720/6
= 120 degree
Question 20 :
If the perimeter of the triangle shown above is the circumference of a circle, then what is the radius of the circle?
Perimeter of triangle = Sum of lengths of all sides
Let "x" be the length of unknown side.
(5π)2 = (4π)2 + x2
25π2 - 16π2 = x2
x2 = 9π2
x = 3π
Perimeter of triangle = 3π + 5π + 4π
Circumference of circle = 12 π
2π r = 12π
r = 6
Hence the radius of circle is 6
After having gone through the stuff given above, we hope that the students would have understood, how to solve math problems in PSAT.
Apart from the stuff given in this section, please use our google custom search here.
You can also visit our following web pages on different stuff in math.
APTITUDE TESTS ONLINE
ACT MATH ONLINE TEST
TRANSFORMATIONS OF FUNCTIONS
ORDER OF OPERATIONS
Converting customary units worksheet
Customary units worksheet
Integers and absolute value worksheets
Nature of the roots of a quadratic equation worksheets
Trigonometry heights and distances
MATH FOR KIDS
Word problems on linear equations
Trigonometry word problems
Word problems on mixed fractrions
Converting repeating decimals in to fractions